275 Page 4 of 16 Eur. Phys. J. C (2019) 79 :275
solution, f (r) must be real valued. So, we must consider
the value of radial co-ordinate (r) such that the term under
square root in (16) must be non-negative. For the case, 1 −
4 ˜α/l
2
≥ 0, that will always be non-negative. But for 1 −
4 ˜α/l
2
< 0, there will be some values of r for which that term
can be negative, so, for those values of r our solution is no
more real valued. Hence, we can say that the Gauss–Bonnet
coupling constant ˜α must lie in the interval [0, l
2
/4]. Besides,
the causality of dual theory demands another constraint on
Gauss–Bonnet coupling constant [67,68]
−
(3D − 1)(D − 3)
4(D + 1)
2
l
2
≤˜α ≤
(D − 3)(D − 4)(D
2
− 3D + 8)
4(D
2
− 5D + 10)
2
l
2
(18)
Thesolution(14) with (16) is a general spherically symmetric
D-dimensional solution of EGB theory coupled to nonlinear
electrodynamics in an AdS spacetime thereby generalizing
the Bardeen solution. The special case in which charge e = 0
and = 0, one get the Boulware–Deser solution [43]. It see
that solution (14) with (16) gets for other field equation. For
definiteness, henceforth, we shall call solution (16) Bardeen–
EGB–AdS black holes. In the case of no charge e = 0, Eq.
(16) reduces to D-dimensional EGB–AdS black holes [59,
60,63,69–74] and in the limit, α → 0, the negative branch
of (16)toD- dimensional Bardeen–AdS black holes [39]
ds
2
=−
1 −
μ
r
2
(r
D−2
+ e
D−2
)
D−1
D−2
+
r
2
l
2
dt
2
+
1
1 −
μ
r
2
(r
D−2
+e
D−2
)
D−1
D−2
+
r
2
l
2
dr
2
+r
2
˜γ
ij
dx
i
dx
j
.
(19)
Further, the solution also goes over to Schwarzschild–
Tangherlini black hole [75] in the absence of charge. To study
the structure of solution, we take limit r → 0 to obtain
f (r) = 1 +
r
2
l
2
ef f
, (20)
where (1/l
2
ef f
) is effective AdS length, it reads
1
l
2
ef f
=
1
2 ˜α
1 −
1 +
4μ
˜α
e
D−1
−
4 ˜α
l
2
, (21)
which is describing a de Sitter solution for ˜α>0inthe
Bardeen–EGB–AdS black hole. When, we take r e,we
get
f (r) ≈ 1 +
r
2
2 ˜α
⎡
⎣
1 −
1 +
4 ˜αμ
r
D−1
+
−
D − 1
D − 2
4 ˜αμ
e
D−2
r
2D−3
+
−
4 ˜α
l
2
+ O
e
2D−4
r
3D−5
+
⎤
⎦
. (22)
From Eq. (22), one can easily notice that the charge density
for our Bardeen–EGB–AdS solution is falling by 1/r
2D−3
+
,
but when we look for the charged EGB black hole [76], it
falls by 1/r
2D−4
+
.
The regularity of the black hole solution (16) can be seen
by behaviour of the scalar invariants, which are given by
lim
r→0
R =
D(D − 1)
2 ˜α
−1 +
1 +
4μ
˜α
e
D−1
−
4 ˜α
l
2
1/2
,
lim
r→0
R =
D(D − 1)
2
2 ˜α
2
1 +
2μ
˜α
e
D−1
−
2 ˜α
l
2
−
1 +
4μ
˜α
e
D−1
−
4 ˜α
l
2
1/2
,
lim
r→0
K =
D(D − 1)
˜α
2
1 +
2μ
˜α
e
D−1
−
2 ˜α
l
2
−
1 +
4μ
˜α
e
D−1
−
4 ˜α
l
2
1/2
. (23)
Thus, the spacetime is regular everywhere as seen from the
behavior of the invariants if e = 0 and l = 0. The D-
dimensional Bardeen–EGB–AdS black hole solution is well
defined everywhere by its curvature invariants.
The weak energy condition states that T
ab
t
a
t
b
≥ 0for
all time like vectors t
a
, i.e., the local energy density cannot
be negative for any observer. The dominant energy condition
states that T
ab
t
a
t
b
≥ 0 and T
ab
t
b
must be space like, for
any time like vector t
a
. Hence, the energy conditions require
ρ ≥ 0 and ρ + P
i
≥ 0,
ρ +P
2
=ρ +P
3
=ρ +P
4
= β
(D − 2)μ
e
D−2
(r
D−3
+ e
D−3
)
2D−3
D−2
. (24)
Where β = (D − 1) and (D − 4) are, respectively, for even
and odd dimensions. It is worthwhile to note that ρ>P
3
and
P
1
=−ρ. Thus the Bardeen–EGB–AdS black holes obey the
weak energy condition.
Next, we proceed to discuss the horizon structure of our
Bardeen–EGB–AdS black holes. The horizons radius, if
exists, are zeros of g
rr
= f (r) = 0. The numerical analysis
of f (r) = 0 reveals that it is possible to find non-vanishing
value of α and e for which metric function f (r) is minimum,
i.e, f (r) = 0 admits two roots r
±
. The smaller and larger
roots, respectively, corresponds to the Cauchy and event hori-
zon of the black holes. We have shown that for a given value
of α and fixed μ
, there exists a critical charge parameter
e
E
, and critical horizon radius r
E
, such that f (r
E
) = 0 has
a double root, i.e, r
E
= r
±
. This case corresponds to the
123