Show how the value 0xabcdef12 would be arranged in memory of a little-endian and a big-endian machine. Assume the data is stored starting at address 0.
时间: 2024-03-21 18:42:29 浏览: 164
内存分配顺序和大小端模式
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Sure!
If the value 0xabcdef12 is stored in memory of a little-endian machine, it would be arranged as follows:
```
Address: 0x00 0x01 0x02 0x03
Value: 0x12 0xef 0xcd 0xab
```
In a little-endian machine, the least significant byte (LSB) is stored at the lowest address, and the most significant byte (MSB) is stored at the highest address.
If the value 0xabcdef12 is stored in memory of a big-endian machine, it would be arranged as follows:
```
Address: 0x00 0x01 0x02 0x03
Value: 0xab 0xcd 0xef 0x12
```
In a big-endian machine, the MSB is stored at the lowest address, and the LSB is stored at the highest address.
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