12步差分用python3代码实现
时间: 2023-11-20 16:04:58 浏览: 88
以下是一个简单的Python 3代码实现12步差分:
```python
def diff12(data):
# 计算一阶差分(前向)
diff1 = []
for i in range(len(data) - 1):
diff1.append(data[i+1] - data[i])
# 计算一阶差分(后向)
diff1_back = []
for i in range(1, len(data)):
diff1_back.append(data[i] - data[i-1])
# 计算二阶差分
diff2 = []
for i in range(len(diff1) - 1):
diff2.append(diff1[i+1] - diff1[i])
# 计算二阶差分(后向)
diff2_back = []
for i in range(1, len(diff1)):
diff2_back.append(diff1[i] - diff1[i-1])
# 计算三阶差分
diff3 = []
for i in range(len(diff2) - 1):
diff3.append(diff2[i+1] - diff2[i])
# 计算三阶差分(后向)
diff3_back = []
for i in range(1, len(diff2)):
diff3_back.append(diff2[i] - diff2[i-1])
# 返回所有差分结果
return [diff1, diff1_back, diff2, diff2_back, diff3, diff3_back]
```
使用示例:
```python
data = [1, 2, 4, 7, 11, 16, 22, 29, 37, 46]
diffs = diff12(data)
print(diffs)
```
输出结果:
```
[[1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1, 1], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0]]
```
其中,每个列表代表一阶、二阶、三阶差分的结果,其中前向和后向的结果分别在两个列表中。
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