狼羊菜代码
时间: 2023-07-02 14:20:11 浏览: 113
农夫狼羊菜的c语言实现代码
狼羊菜问题是传统的人工智能领域的一个经典问题,它的简述如下:
有一只狼、一只羊和一棵菜,它们需要一起过河。但是,小船只能装下你和另外一样东西,你必须把它们全部运到对岸。如果你不在场,狼会吃掉羊,羊会吃掉菜。请问你应该如何安排它们的顺序才能安全地过河?
这个问题可以用深度优先搜索、广度优先搜索、A*搜索等算法来解决。下面是一个简单的 Python 代码实现:
```
# 定义状态类
class State:
def __init__(self, wolf, sheep, vegetable, boat):
self.wolf = wolf # 狼的位置
self.sheep = sheep # 羊的位置
self.vegetable = vegetable # 菜的位置
self.boat = boat # 船的位置
# 定义状态比较函数
def __eq__(self, other):
return self.wolf == other.wolf and self.sheep == other.sheep and self.vegetable == other.vegetable and self.boat == other.boat
# 定义状态哈希函数
def __hash__(self):
return hash((self.wolf, self.sheep, self.vegetable, self.boat))
# 定义状态是否合法的函数
def is_valid(self):
if self.sheep == self.vegetable and self.sheep != self.boat:
return False
if self.wolf == self.sheep and self.wolf != self.boat:
return False
return True
# 定义深度优先搜索函数
def dfs(state, visited, path):
if state not in visited:
visited.add(state)
if state.boat == "left" and state.is_valid():
if state == State("right", "right", "right", "right"):
path.append(state)
return True
for next_state in get_next_states(state):
if dfs(next_state, visited, path):
path.append(state)
return True
elif state.boat == "right" and state.is_valid():
if state == State("left", "left", "left", "left"):
path.append(state)
return True
for next_state in get_next_states(state):
if dfs(next_state, visited, path):
path.append(state)
return True
return False
# 定义获取下一个状态的函数
def get_next_states(state):
next_states = []
if state.boat == "left":
# 狼过河
if state.wolf == "left":
next_state = State("right", state.sheep, state.vegetable, "right")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State("left", state.sheep, state.vegetable, "right")
if next_state.is_valid():
next_states.append(next_state)
# 羊过河
if state.sheep == "left":
next_state = State(state.wolf, "right", state.vegetable, "right")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State(state.wolf, "left", state.vegetable, "right")
if next_state.is_valid():
next_states.append(next_state)
# 菜过河
if state.vegetable == "left":
next_state = State(state.wolf, state.sheep, "right", "right")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State(state.wolf, state.sheep, "left", "right")
if next_state.is_valid():
next_states.append(next_state)
else:
# 狼过河
if state.wolf == "right":
next_state = State("left", state.sheep, state.vegetable, "left")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State("right", state.sheep, state.vegetable, "left")
if next_state.is_valid():
next_states.append(next_state)
# 羊过河
if state.sheep == "right":
next_state = State(state.wolf, "left", state.vegetable, "left")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State(state.wolf, "right", state.vegetable, "left")
if next_state.is_valid():
next_states.append(next_state)
# 菜过河
if state.vegetable == "right":
next_state = State(state.wolf, state.sheep, "left", "left")
if next_state.is_valid():
next_states.append(next_state)
else:
next_state = State(state.wolf, state.sheep, "right", "left")
if next_state.is_valid():
next_states.append(next_state)
return next_states
# 测试
start_state = State("left", "left", "left", "left")
visited = set()
path = []
dfs(start_state, visited, path)
for state in reversed(path):
print(state.wolf, state.sheep, state.vegetable, state.boat)
```
该代码实现了深度优先搜索来解决狼羊菜问题,其中包括定义状态类、状态比较函数、状态哈希函数、状态是否合法的函数、获取下一个状态的函数以及深度优先搜索函数。
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