帮我修改这段代码Week_dic = dic("1":"Mon","2":"Tue","3":"Wed","4":"Thu","5":"Fri"\ ,"6":"Sat","7":"Sun") n =input() print(Week_dic(n))
时间: 2023-09-16 09:11:47 浏览: 24
好的,这段代码的问题在于 dic 函数的语法是错误的,应该是 dictionary 函数。同时,在字典中,键值应该用冒号分隔,而不是双引号。以下是更正后的代码:
Week_dic = {"1": "Mon", "2": "Tue", "3": "Wed", "4": "Thu", "5": "Fri", "6": "Sat", "7": "Sun"}
n = input()
print(Week_dic.get(n))
请注意,使用 get 方法可以避免在字典中查找不存在的键而导致的 KeyError 错误。
相关问题
C# 中nt max_week = std::max({week1, week2, week3, week4, week5, week6, week7}); 返回最大值
在 C# 中,你可以使用 Math.Max 方法来获取给定数字中的最大值。以下是使用该方法找到给定数字的最大值的示例代码:
```csharp
int max_week = Math.Max(week1, Math.Max(week2, Math.Max(week3, Math.Max(week4, Math.Max(week5, Math.Max(week6, week7))))));
```
在这里,我们使用嵌套的 Math.Max 方法来比较给定的数字并返回最大值。
for date in date_history.date: week_day = date.weekday() # 获取星期几,0 表示星期一,6 表示星期日 sum_week.append(week_day) week_list = [] for i, num in enumerate(sum_week): if num == 6: week_list.append(i) forecast_time_obj_week = forecast_time_obj.weekday() # 判断预测的值是否周末 if forecast_time_obj_week == 6: # 判断是否是周日,0代表周一,6代表周日 pre_true_24hour = dataset_history[(week_list[-1] - 95): (week_list[-1] + 1)] else: pre_true_24hour = pre_true 优化代码
可以考虑使用列表解析式来代替循环生成 sum_week 列表,代码如下:
```
sum_week = [date.weekday() for date in date_history.date]
```
同时,可以使用列表的 index 方法来查找 sum_week 列表中所有 6 的位置,代码如下:
```
week_list = [i for i, num in enumerate(sum_week) if num == 6]
```
这样可以避免使用循环生成 week_list 列表。另外,可以将判断是否是周日的代码提取出来,避免在判断是否是周日时重复计算,代码如下:
```
if forecast_time_obj_week == 6: # 判断是否是周日,0代表周一,6代表周日
pre_true_24hour = dataset_history[(week_list[-1] - 95): (week_list[-1] + 1)]
else:
pre_true_24hour = pre_true
```