SELECT a.project_name AS projectName, a.order_no AS orderNo, workHourPlan AS workHourPlan FROM t_project_plan_management a WHERE a.reserve3 != '1' workHourPlan IN ( SELECT SUM(TRUNCATE( b.work_hour , 2 ) ) FROM t_work_hour b WHERE b.order_no = a.order_no )错在哪

在这个 SQL 语句中，您的 WHERE 子句中缺少一个逻辑运算符。应该在 `a.reserve3 != '1'` 之后添加 `AND` 连接符。

这是修改后的 SQL 语句：

SELECT 
    a.project_name AS projectName, 
    a.order_no AS orderNo, 
    workHourPlan AS workHourPlan 
FROM 
    t_project_plan_management a 
WHERE 
    a.reserve3 != '1' 
    AND workHourPlan IN (
        SELECT 
            SUM(TRUNCATE(b.work_hour, 2)) 
        FROM 
            t_work_hour b 
        WHERE 
            b.order_no = a.order_no
    )

这样修改后，SQL 语句就可以正确执行了。

相关问题

为什么下面的sql语句会输出重复的结果：SELECT tp.parent_production_orders AS parent_production_orders, tp.production_orders AS production_orders, tp.work_order AS work_order, tp.contract AS contract, tp.sbbh AS sbbh, tp.batch_num AS batch_num, tp.product_code AS product_code, tp.product_number AS product_number, tp.product_name AS product_name, to_char( middle.create_date, 'yyyy-mm-dd' ) AS issued_date, to_char( to_timestamp( tp.delivery_time / 1000 ), 'yyyy-mm-dd' ) AS delivery_time, middle.line_code AS work_area_code, middle.line_name AS work_area_name, tp.workorder_number AS workorder_number, tp.complete_number AS complete_number, tp.part_unit AS part_unit, middle.work_time_type AS work_time_type, middle.process_time AS process_time, CASE WHEN sc.totalSubmitHours IS NULL THEN 0 ELSE sc.totalSubmitHours END AS submit_work_hours, CASE WHEN middle.process_time > 0 AND sc.totalSubmitHours IS NOT NULL THEN round( ( sc.totalSubmitHours / middle.process_time ), 2 ) * 100 ELSE 0 END plan_achievement_rate, CASE WHEN sc.totalSubmitHours IS NULL THEN 0 ELSE round( CAST ( sc.totalSubmitHours AS NUMERIC ) / CAST ( 60 AS NUMERIC ), 1 ) END AS submit_work_hours_h, round( CAST ( middle.process_time AS NUMERIC ) / CAST ( 60 AS NUMERIC ), 1 ) AS process_time_h, pinfo.material_channel AS material_channel FROM hm_model_work_order_report_middle middle LEFT JOIN hm_model_trc_plan tp ON middle.work_order = tp.work_order LEFT JOIN ( SELECT oro.work_order AS orderNo, oro.work_area_code AS lineCode, SUM ( submit_work_hours ) AS totalSubmitHours, '自制' AS workHourType FROM hm_model_trc_order_report_operation_u orou LEFT JOIN hm_model_trc_order_report_operation oro ON orou.work_order_process_id = oro.ID WHERE orou.work_order_process_id IS NOT NULL AND oro.work_area_code IS NOT NULL GROUP BY oro.work_order, oro.work_area_code UNION all SELECT ohs.work_order_no AS orderNo, ohs.line_code AS lineCode, SUM ( receiving_hour ) AS totalSubmitHours, '外委' AS workHourType FROM hm_model_outsourcing_hour_statistics ohs GROUP BY ohs.work_order_no, ohs.line_code ) sc ON middle.work_order = sc.orderNo AND middle.line_code = sc.lineCode AND middle.work_time_type = sc.workHourType LEFT JOIN hm_model_part_info AS pinfo ON tp.product_number = pinfo.part_code WHERE middle.process_time > 0 AND tp.delivery_time IS NOT NULL AND tp.production_orders LIKE'FJ2023051100286' ORDER BY to_char( to_timestamp( tp.delivery_time / 1000 ), 'yyyy-mm-dd' ) DESC, tp.parent_production_orders DESC, tp.node_level ASC

可能是因为查询结果中有多个相同的记录，即存在多个记录的各个字段的值都相同，因此会出现重复的结果。可以使用 DISTINCT 关键字去除重复的记录。例如：SELECT DISTINCT tp.parent_production_orders AS parent_production_orders, tp.production_orders AS production_orders, ... （省略后面的 SQL 语句）。另外，还可以检查查询条件是否合理，是否需要增加更多的条件来过滤数据。

SELECT z.id, z.id_card idCard, z.rdid, z.order_no orderNo, z.auth_no authNo, z.STATUS, z.pay_state payState, z.amount, z.glc, z.libcode, z.create_time createTime, z.payment_time paymentTime, z.create_rdid_error createRdidError, o.NAME libName FROM zhima_order_2022 z LEFT JOIN opac_site_config o ON o.glc = z.glc WHERE z.id_card = '652324197811090524' 使用 exist 代替

好的，您的问题是如何使用 exist 代替子查询查询 zhima_order_2022 表中 id_card 为 '652324197811090524' 的记录是否存在？

使用 exist 可以将子查询改写为关键字，优化查询性能。具体的 SQL 语句如下：

SELECT z.id, z.id_card idCard, z.rdid, z.order_no orderNo, z.auth_no authNo, z.STATUS, z.pay_state payState, z.amount, z.glc, z.libcode, z.create_time createTime, z.payment_time paymentTime, z.create_rdid_error createRdidError, o.NAME libName 
FROM zhima_order_2022 z 
LEFT JOIN opac_site_config o ON o.glc = z.glc 
WHERE EXISTS (
    SELECT 1 FROM zhima_order_2022 WHERE id_card = '652324197811090524'
);

这条 SQL 语句中，使用了 exist 关键字，判断是否存在 id_card 为 '652324197811090524' 的记录。如果存在，则返回主查询中的字段，否则不返回任何记录。