计算1!+2!+3!+...+10!的值并输出
时间: 2023-11-13 14:54:20 浏览: 42
1! = 1
2! = 2 * 1 = 2
3! = 3 * 2 * 1 = 6
4! = 4 * 3 * 2 * 1 = 24
5! = 5 * 4 * 3 * 2 * 1 = 120
6! = 6 * 5 * 4 * 3 * 2 * 1 = 720
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040
8! = 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40320
9! = 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 362880
10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800
因此,1!+2!+3!+...+10!的值为:1 + 2 + 6 + 24 +120 +720 +5040 +40320 +362880 +3628800 = 4037913
相关问题
编写程序,计算并输出 1!+2!+3!+...+10!的值
可以使用循环和递归两种方式来计算1!+2!+3!+...+10!的值。
循环方式:
```
#include <stdio.h>
int main() {
int i, j, sum = 0, factorial = 1;
for (i = 1; i <= 10; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
printf("1!+2!+3!+...+10! = %d\n", sum);
return 0;
}
```
递归方式:
```
#include <stdio.h>
int factorial(int n) {
if (n == 1) {
return 1;
} else {
return n * factorial(n - 1);
}
}
int main() {
int i, sum = 0;
for (i = 1; i <= 10; i++) {
sum += factorial(i);
}
printf("1!+2!+3!+...+10! = %d\n", sum);
return 0;
}
```
以上两种方式都可以得到1!+2!+3!+...+10!的值为 4037913。
计算1!+2!+3!+10!
以下是两种Python计算1!+2!+3!+...+n!的方法:
1.使用for循环来计算
```python
n = 10
sum = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += factorial
print(sum) # 输出:4037913
```
2.使用递归函数调用阶乘方法求和(其中n的值在1~40之间)
```python
def factorial(n):
if n == 1:
return 1
else:
return n * factorial(n-1)
n = 10
sum = 0
for i in range(1, n+1):
sum += factorial(i)
print(sum) # 输出:4037913
```