rrt算法 matlab代码
时间: 2023-08-26 22:06:56 浏览: 66
rrt算法的matlab代码-ENPM661-Informed-RRT-Star:该存储库包含基于采样的算法RRT、RRT*和Informed
以下是一个简单的RRt算法的Matlab实现,供您参考:
```
% RRT algorithm implementation in Matlab
% Define parameters
q_start = [0, 0]; % Starting configuration
q_goal = [10, 10]; % Goal configuration
delta_q = 0.5; % Step size
max_iter = 1000; % Maximum number of iterations
obstacles = [4, 4, 1; 6, 6, 1]; % Obstacle positions
% Initialize tree
tree = [q_start, 0];
% Iterate until goal is reached or maximum number of iterations is reached
for i = 1:max_iter
% Generate random configuration
q_rand = [rand() * 10, rand() * 10];
% Find nearest node in tree
distances = vecnorm(tree(:,1:2) - q_rand, 2, 2);
[min_distance, nearest_node_index] = min(distances);
nearest_node = tree(nearest_node_index, 1:2);
% Calculate new node position
if min_distance < delta_q
q_new = q_rand;
else
q_new = nearest_node + (q_rand - nearest_node) * delta_q / min_distance;
end
% Check if new node is collision-free
if ~check_collision(q_new, obstacles)
% Add new node to tree
new_node_index = size(tree, 1) + 1;
tree(new_node_index, :) = [q_new, nearest_node_index];
% Check if goal is reached
if vecnorm(q_new - q_goal, 2) < delta_q
break;
end
end
end
% Reconstruct path from goal to start
path = [q_goal, size(tree, 1)];
while path(end) ~= 1
path(end+1) = tree(path(end), 3);
end
path = flipud(tree(path, 1:2));
% Plot result
figure();
hold on;
plot(q_start(1), q_start(2), 'ro');
plot(q_goal(1), q_goal(2), 'rx');
for i = 1:size(obstacles, 1)
rectangle('Position', [obstacles(i,1)-obstacles(i,3)/2, obstacles(i,2)-obstacles(i,3)/2, obstacles(i,3), obstacles(i,3)], 'Curvature', [1, 1], 'FaceColor', 'k');
end
plot(tree(:,1), tree(:,2), 'b.');
plot(path(:,1), path(:,2), 'r');
axis equal;
function collision = check_collision(q, obstacles)
% Check if configuration is collision-free
for i = 1:size(obstacles, 1)
if vecnorm(q - obstacles(i, 1:2), 2) <= obstacles(i, 3)
collision = true;
return;
end
end
collision = false;
end
```
这个实现采用了比较简单的随机采样和最近邻搜索方法,可以处理简单的平面路径规划问题。您可以根据需要进行修改和扩展。
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