for (int i = 0; i < Math.min(10, inflList.size()); i++) { int u = inflList.get(i).getKey(); int infl = inflList.get(i).getValue(); System.out.printf("节点 %d,影响力:%d\n", u, infl); 解释这段代码
时间: 2024-04-29 21:20:07 浏览: 20
这段代码的作用是输出 `inflList` 中影响力前 10 名的节点编号和影响力值。
具体来说,`for` 循环中的 `i` 从 0 开始,每次循环加 1,直到 `Math.min(10, inflList.size())`(即 10 和 `inflList` 的长度中较小的值)为止。在循环体中,通过 `inflList.get(i)` 方法获取 `inflList` 中第 `i` 个元素,即一个 `Map.Entry<Integer, Integer>` 对象,然后通过 `.getKey()` 和 `.getValue()` 方法获取其键和值,分别赋值给 `u` 和 `infl`。
最后,通过 `System.out.printf(...)` 方法输出节点编号和影响力值,其中 `%d` 表示输出一个整数,`\n` 表示换行。整个循环的作用是输出 `inflList` 中影响力前 10 名的节点编号和影响力值。
相关问题
int max = Integer.MIN_VALUE; for (int i = 0; i < arr.length; i++) { max = Math.max(max, arr[i]); }
The code above finds the maximum value in an integer array called "arr".
The variable "max" is initialized to the minimum possible integer value using the constant "Integer.MIN_VALUE".
Then, a for loop is used to iterate through each element of the array. The loop starts at index 0 and continues until it reaches the end of the array (arr.length).
In each iteration, the Math.max() method is used to compare the current element of the array with the current maximum value stored in the "max" variable. If the current element is greater than the current maximum value, it becomes the new maximum.
After the loop finishes, the "max" variable holds the maximum value in the array.
#include<iostream> #include<string> #include<math.h> using namespace std; int main(){ int m,n; cin>>m>>n; int a[m+5][n+5]; for(int i=1;i<=m;i++) for(int j=1;j<=n;j++) cin>>a[i][j]; int r,s; cin>>r>>s; int b[r+5][s+5]; for(int i=1;i<=r;i++) for(int j=1;j<=s;j++) cin>>b[i][j]; int minX=1; int minY=1; int min=10000000; for(int u=1;u<=m-r+1;u++) for(int v=1;v<=n-s+1;v++){ int sum=0; for(int i=1;i<=r;i++){ for(int j=1;j<=s;j++){ sum+=abs(a[u+i-1][v+j-1]-b[i][j]); } } if(sum<min){ minX=u; minY=v; min=sum; } } for(int i=1;i<=r;i++){ for(int j=1;j<=s;j++){ cout<<a[minX+i-1][minY+j-1]<<' '; } cout<<endl; } return 0; }改为c语言
把代码中的"cout"改为"printf",去掉命名空间,整体代码如下:
#include <stdio.h>
#include <string.h>
#include <math.h>
int main() {
int m, n;
scanf("%d%d", &m, &n);
int a[m + 5][n + 5];
for (int i = 1; i <= m; i++)
for (int j = 1; j <= n; j++)
scanf("%d", &a[i][j]);
int r, s;
scanf("%d%d", &r, &s);
int b[r + 5][s + 5];
for (int i = 1; i <= r; i++)
for (int j = 1; j <= s; j++)
scanf("%d", &b[i][j]);
int minX = 1;
int minY = 1;
int min = 10000000;
for (int u = 1; u <= m - r + 1; u++)
for (int v = 1; v <= n - s + 1; v++) {
int sum = 0;
for (int i = 1; i <= r; i++) {
for (int j = 1; j <= s; j++) {
sum += abs(a[u + i - 1][v + j - 1] - b[i][j]);
}
}
if (sum < min) {
minX = u;
minY = v;
min = sum;
}
}
for (int i = 1; i <= r; i++) {
for (int j = 1; j <= s; j++) {
printf("%d ", a[minX + i - 1][minY + j - 1]);
}
printf("\n");
}
return 0;
}
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