用C语言写一段模糊PID算法
时间: 2024-10-23 10:07:42 浏览: 43
在C语言中,编写一个简单的模糊PID(Proportional-Integral-Derivative)控制器需要一些数学库支持,因为PID涉及到连续运算。这里是一个简化版的模糊化PID控制算法的示例:
```c
#include <stdio.h>
#include <math.h>
#define SETPOINT 50
#define MAX_OUTPUT 100
#define MIN_OUTPUT -100
#define FLOOR(x) ((x) > 0 ? (x) : 0)
#define CEIL(x) ((x) < 0 ? (x) : 0)
// 模糊化函数
int fuzzy_input(float input, int low_range[], int high_range[], int num_rules) {
int output = 0;
float ratio = input * (high_range[0] - low_range[0]) / (SETPOINT - low_range[0]);
for (int i = 0; i < num_rules; i++) {
if (ratio >= low_range[i] && ratio <= high_range[i]) {
output = i + 1;
break;
}
}
return output;
}
void pid_controller(float error, float integral, float derivative, float &output) {
// 使用简单模糊规则
static int last_error = 0;
int p_rule = fuzzy_input(error, {-10, 0, 10}, {0, 10, 20}, 3); // Proportional
int i_rule = fuzzy_input(integral, {0, 20, 40}, {40, 60, 80}, 3); // Integral
int d_rule = fuzzy_input(derivative, {-10, 0, 10}, {0, 10, 20}, 3); // Derivative
// 简单的比例、积分和微分部分
output = FLOOR(MAX_OUTPUT * (p_rule / 10.0)) +
FLOOR(MAX_OUTPUT * (i_rule / 60.0)) -
FLOOR(MAX_OUTPUT * (d_rule / 20.0));
// 清零积分,模拟实际应用中积分限幅
integral = integral + error;
if (integral > MAX_OUTPUT) integral = MAX_OUTPUT;
else if (integral < MIN_OUTPUT) integral = MIN_OUTPUT;
// 更新误差
last_error = error;
}
int main() {
float error, integral = 0, derivative = 0, output = 0;
float current_value = 0; // 假设当前传感器值
while (1) {
error = SETPOINT - current_value;
derivative = error - last_error;
pid_controller(error, integral, derivative, output);
printf("Error: %.2f, Output: %.2f\n", error, output);
// 这里假设我们有一个模拟系统来改变current_value,比如读取ADC值
// current_value = ...;
last_error = error;
}
return 0;
}
```
这个示例展示了如何使用模糊逻辑来调整PID控制器的参数,每个输入变量(误差、积分、微分)都被转换到0-10范围内的模糊等级,然后根据比例、积分和微分的模糊程度计算输出。请注意,这只是一个基础演示,真正的工业级PID控制器会更复杂,并可能包含PID参数调整和自适应能力。
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