能否给我的代码每一行都加上注释:for k=1:n2 for n=1:n1 eq1=det([x-xy(i(n),:);xy(j(n),:)-xy(i(n),:)]); eq2=(x-cxy(k,:))*(xy(j(n),:)-xy(i(n),:))'; [sx,sy]=solve(eq1,eq2);sx=double(sx);sy=double(sy); if all([min(xy([i(n),j(n)],1))<=sx,sx<=max(xy([i(n),j(n)],1)); min(xy([i(n),j(n)],2))<=sy,sy<=max(xy([i(n),j(n)],2))]) P(n,k)=sx;Q(n,k)=sy; d(n,k)=abs(det([xy(i(n),:)-cxy(k,:);xy(j(n),:)-cxy(k,:)])); norm (xy(i(n),:)-xy(j(n),:)); elseif norm(xy(i(n),:)-cxy(k,:))<norm(xy(j(n),:)-cxy(k,:)) d(n,k)=norm(xy(i(n),:)-cxy(k,:)); P(n,k)=xy(i(n),1);Q(n,k)=xy(i(n),2); else d(n,k)=norm(xy(j(n),:)-cxy (k,:)); P(n,k)=xy(j(n),1);Q(n,k)=xy(j(n),2); end end end
时间: 2023-11-01 15:06:26 浏览: 43
Sure! Here are the comments for the code:
```
% Loop over each column of cxy
for k=1:n2
% Loop over each row of i and j
for n=1:n1
% Compute eq1 and eq2 using x, xy(i(n),:), xy(j(n),:), and cxy(k,:)
eq1=det([x-xy(i(n),:);xy(j(n),:)-xy(i(n),:)]);
eq2=(x-cxy(k,:))*(xy(j(n),:)-xy(i(n),:))';
% Solve for sx and sy using eq1 and eq2, and convert them to double
[sx,sy]=solve(eq1,eq2);
sx=double(sx);
sy=double(sy);
% If (sx, sy) is within the range of (i(n),j(n)), update P, Q, and d
if all([min(xy([i(n),j(n)],1))<=sx,sx<=max(xy([i(n),j(n)],1));
min(xy([i(n),j(n)],2))<=sy,sy<=max(xy([i(n),j(n)],2))])
P(n,k)=sx;
Q(n,k)=sy;
d(n,k)=abs(det([xy(i(n),:)-cxy(k,:);xy(j(n),:)-cxy(k,:)]));
norm (xy(i(n),:)-xy(j(n),:));
% If (sx, sy) is not within the range of (i(n),j(n)), update P, Q, and d based on the closest point
elseif norm(xy(i(n),:)-cxy(k,:))<norm(xy(j(n),:)-cxy(k,:))
d(n,k)=norm(xy(i(n),:)-cxy(k,:));
P(n,k)=xy(i(n),1);
Q(n,k)=xy(i(n),2);
else
d(n,k)=norm(xy(j(n),:)-cxy (k,:));
P(n,k)=xy(j(n),1);
Q(n,k)=xy(j(n),2);
end
end
end
```