用python编写函数实现求1+1+2+3+5+8+...+n的例子
时间: 2024-01-09 21:21:56 浏览: 41
以下是用Python编写的函数实现求1+1+2+3+5+8+...+n的例子:
```python
def fibonacci_sum(n):
if n <= 0:
return "请输入一个正整数"
elif n == 1:
return 1
else:
a, b = 1, 1
sum = a + b
for i in range(2, n):
a, b = b, a + b
sum += b
return sum
n = 10
result = fibonacci_sum(n)
print("1+1+2+3+5+8+...+n的和为:", result) # 输出:1+1+2+3+5+8+...+n的和为: 143
```
相关问题
编写函数求1/2+2/3+3/5+5/8+...的前n项和
以下是一个编写函数求1/2+2/3+3/5+5/8+...的前n项和的例子:
```python
def calculate_sum(n):
numerator = 1
denominator = 2
total_sum = 0
for i in range(n):
total_sum += numerator / denominator
numerator, denominator = denominator, numerator + denominator
return total_sum
n = 5
result = calculate_sum(n)
print("The sum of the first", n, "terms is:", result)
```
这个函数使用了一个循环来计算前n项的和。在每一次循环中,分子和分母的值会根据规律进行更新,然后将当前项的值加到总和中。最后返回总和作为结果。
编写函数,求1!+2!+3!+.....+k!的和
以下是一个编写函数求阶乘和的例子:
```python
def factorial_sum(k):
result = 0
factorial = 1
for i in range(1, k+1):
factorial *= i
result += factorial
return result
k = 5
print("Factorial sum:", factorial_sum(k)) # 输出:Factorial sum: 153
```