给定一棵二叉树的先序遍历序列和中序遍历序列，要求计算该二叉树的高度。用c++写

根据引用[1]和引用的思路，可以先根据给定的先序遍历序列和中序遍历序列构建出该二叉树，然后再计算该二叉树的高度。具体步骤如下：

1.定义二叉树节点结构体，包括节点值、左右子树指针。

struct TreeNode {
    int val;
    TreeNode* left;
    TreeNode* right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

2.定义递归函数buildTree，根据给定的先序遍历序列和中序遍历序列构建二叉树。

TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder, int preStart, int preEnd, int inStart, int inEnd) {
    if (preStart > preEnd) {
        return NULL;
    }
    int rootVal = preorder[preStart];
    int rootIndex = 0;
    for (int i = inStart; i <= inEnd; i++) {
        if (inorder[i] == rootVal) {
            rootIndex = i;
            break;
        }
    }
    int leftSize = rootIndex - inStart;
    TreeNode* root = new TreeNode(rootVal);    root->left = buildTree(preorder, inorder, preStart + 1, preStart + leftSize, inStart, rootIndex - 1);
    root->right = buildTree(preorder, inorder, preStart + leftSize + 1, preEnd, rootIndex + 1, inEnd);
    return root;
}

3.定义递归函数getHeight，计算二叉树的高度。

int getHeight(TreeNode* root) {
    if (root == NULL) {
        return 0;
    }
    int leftHeight = getHeight(root->left);
    int rightHeight = getHeight(root->right);
    return max(leftHeight, rightHeight) + 1;
}

4.在主函数中调用buildTree函数构建二叉树，再调用getHeight函数计算二叉树的高度。

int main() {
    vector<int> preorder = {1, 2, 4, 5, 3, 6};
    vector<int> inorder = {4, 2, 5, 1, 3, 6};
    TreeNode* root = buildTree(preorder, inorder, 0, preorder.size() - 1, 0, inorder.size() - 1);
    int height = getHeight(root);
    cout << "The height of the binary tree is: " << height << endl;
    return 0;
}