Please select the mail server configuration type that best meets your │ needs. │ │ No configuration: │ Should be chosen to leave the current configuration unchanged. │ Internet site: │ Mail is sent and received directly using SMTP. │ Internet with smarthost: │ Mail is received directly using SMTP or by running a utility such │ as fetchmail. Outgoing mail is sent using a smarthost. │ Satellite system: │ All mail is sent to another machine, called a 'smarthost', for │ delivery. │ Local only: │ │ <确定> │什么意思

时间: 2024-02-15 09:28:08 浏览: 239
这是一个关于选择邮件服务器配置类型的提示。其中: - No configuration:选择此选项将保持当前配置不变。 - Internet site:使用SMTP直接发送和接收邮件。 - Internet with smarthost:使用SMTP或运行fetchmail等实用程序直接接收邮件。使用smarthost发送邮件。 - Satellite system:所有邮件都发送到另一台名为“smarthost”的机器上进行投递。 - Local only:仅在本地使用。 在这个提示中,您需要选择最符合您需要的邮件服务器配置类型。确认后,将应用新的配置。
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Make sure that we grade your HW based solely on your R code script. If we don’t see the correct results when we run your code, you will get 0 point for those questions. 1. Create a R function to show the central limit theorem. This function should have the following properties: - In the argument of the function, you have an option to consider poisson, exponential, uniform, normal distributions as the population distribution. - Depending on the choice of the population distribution in part (1), the function will receive extra argument(s) for the parameters of the distribution. For example, if a normal distri- bution is chosen, the mean and SD are needed in the function argument. Note that each distribution has a different parameter setting. - If the distribution is not selected from (“Normal”, “Poisson”, “Uniform”, “Exponential”), the function needs to print the following error message: check the distributional setting: consider ("Normal", "Poisson", "Uniform", "Exponential") and stop. - The function should give the summary statistics (minimum, 1st quartile, median, mean, 3rd quartile, maximum) of 1, 000 sample mean values for given n values (n = 10, 50, 100, 500). - The result should have the following statement at the beginning, for example, if a normal distribution with mean 1 and SD 0.5 was chosen: ‘‘For the Normal distribution, the central limit theorem is tested’’ where the term “Normal” is automatically inserted in the statement based on the argument. And the output should have the following form: For the Normal distribution, the central limit theorem is tested When n=10: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.5187 0.8930 1.0016 0.9993 1.1019 1.4532 When n=50: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.7964 0.9508 1.0010 0.9997 1.0493 1.2309 1 When n=100: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.8534 0.9679 0.9972 0.9992 1.0325 1.1711 When n=500: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.9258 0.9836 1.0006 0.9997 1.0154 1.0678 I Using your own function, test the N(−1,0.52) and the Unif(−3,6) case.

Sure, I can help you with that! Here's the R code for the function that meets the requirements: ```{r} central_limit_theorem <- function(distribution, ...) { # check if the selected distribution is valid if (!(distribution %in% c("Normal", "Poisson", "Uniform", "Exponential"))) { message("Check the distributional setting: consider ('Normal', 'Poisson', 'Uniform', 'Exponential')") stop() } # create a vector of n values to test n_values <- c(10, 50, 100, 500) # create a data frame to store the summary statistics results <- data.frame(matrix(ncol = length(n_values) + 1, nrow = 6)) # set the column names colnames(results) <- c("Statistic", paste0("n=", n_values)) # set the row names rownames(results) <- c("Min.", "1st Qu.", "Median", "Mean", "3rd Qu.", "Max.") # generate 1000 sample means for each n value for (i in seq_along(n_values)) { # set the sample size n <- n_values[i] # generate 1000 sample means sample_means <- replicate(1000, mean(rdist(distribution, n = n, ...))) # calculate the summary statistics and store them in the results data frame results[, i + 1] <- round(summary(sample_means), 4) } # create the output statement output_statement <- paste0("For the ", distribution, " distribution, the central limit theorem is tested") # print the output statement and the summary statistics cat(output_statement, "\n") print(results) } # create a helper function to generate random numbers from different distributions rdist <- function(distribution, n, ...) { switch(distribution, "Normal" = rnorm(n, ...), "Poisson" = rpois(n, ...), "Uniform" = runif(n, ...), "Exponential" = rexp(n, ...)) } # test the function with Normal distribution with mean -1 and SD 0.5 central_limit_theorem("Normal", mean = -1, sd = 0.5) # test the function with Uniform distribution with minimum -3 and maximum 6 central_limit_theorem("Uniform", min = -3, max = 6) ``` Hope this helps! Let me know if you have any questions.

ERROR : Error appeared during Puppet run: 192.168.187.131_controller.pp Notice: /Stage[main]/Nova::Db::Sync/Exec[nova-db-sync]/returns: Error: (pymysql.err.OperationalError) (1045, u"Access denied for user 'nova'@'192.168.187.131' (using password: YES)") (Background on this error at: http://sqlalche.me/e/e3q8) You will find full trace in log /var/tmp/packstack/20230607-102328-geDcuy/manifests/192.168.187.131_controller.pp.log Please check log file /var/tmp/packstack/20230607-102328-geDcuy/openstack-setup.log for more information Additional information: * Parameter CONFIG_NEUTRON_L2_AGENT: You have chosen OVN Neutron backend. Note that this backend does not support the VPNaaS or FWaaS services. Geneve will be used as the encapsulation method for tenant networks * A new answerfile was created in: /root/packstack-answers-20230607-102330.txt * Time synchronization installation was skipped. Please note that unsynchronized time on server instances might be problem for some OpenStack components. * Warning: NetworkManager is active on 192.168.187.131. OpenStack networking currently does not work on systems that have the Network Manager service enabled. * File /root/keystonerc_admin has been created on OpenStack client host 192.168.187.131. To use the command line tools you need to source the file. * To access the OpenStack Dashboard browse to http://192.168.187.131/dashboard .

根据你提供的错误信息,看起来在运行 Puppet manifests 的时候,出现了一个数据库访问错误。具体来说,nova 用户在访问数据库时,被拒绝了,因为密码不正确。这可能是因为密码被修改了,或者是配置文件中的密码被错误地设置了。你可以检查一下 nova 用户的数据库访问权限和密码是否正确,或者尝试重新设置密码。此外,也可以查看一下 /var/tmp/packstack/20230607-102328-geDcuy/manifests/192.168.187.131_controller.pp.log 日志文件,获取更详细的信息。另外,还有一些其他的警告信息,比如 NetworkManager 服务正在运行,需要注意。建议你认真阅读这些信息,并进行相应的操作。
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用C++编写程序,实现以下问题2、题目ID Codes(POJ1146) Time Limit: 1000MS Memory Limit: 10000K 描述: It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical measure--all citizens are to have a tiny microcomputer surgically implanted in their left wrists. This computer will contains all sorts of personal information as well as a transmitter which will allow people's movements to be logged and monitored by a central computer. (A desirable side effect of this process is that it will shorten the dole queue for plastic surgeons.) An essential component of each computer will be a unique identification code, consisting of up to 50 characters drawn from the 26 lower case letters. The set of characters for any given code is chosen somewhat haphazardly. The complicated way in which the code is imprinted into the chip makes it much easier for the manufacturer to produce codes which are rearrangements of other codes than to produce new codes with a different selection of letters. Thus, once a set of letters has been chosen all possible codes derivable from it are used before changing the set. For example, suppose it is decided that a code will contain exactly 3 occurrences of a', 2 of b' and 1 of c', then three of the allowable 60 codes under these conditions are: abaabc abaacb ababac These three codes are listed from top to bottom in alphabetic order. Among all codes generated with this set of characters, these codes appear consecutively in this order. Write a program to assist in the issuing of these identification codes. Your program will accept a sequence of no more than 50 lower case letters (which may contain repeated characters) and print the successor code if one exists or the message No Successor' if the given code is the last in the sequence for that set of characters. 输入: Input will consist of a series of lines each containing a string representing a code. The entire file will be terminated by a line consisting of a single #. 输出: Output will consist of one line for each code read containing the successor code or the words 'No Successor'. 样例输入 abaacb cbbaa # 样例输出 ababac No Successor

Mircea has n pictures. The i-th picture is a square with a side length of si centimeters. He mounted each picture on a square piece of cardboard so that each picture has a border of w centimeters of cardboard on all sides. In total, he used c square centimeters of cardboard. Given the picture sizes and the value c, can you find the value of w? A picture of the first test case. Here c=50=52+42+32, so w=1 is the answer. Please note that the piece of cardboard goes behind each picture, not just the border. Input The first line contains a single integer t (1≤t≤1000) — the number of test cases. The first line of each test case contains two positive integers n (2≤n≤2⋅105) and c (1≤c≤1018) — the number of paintings, and the amount of used square centimeters of cardboard. The second line of each test case contains n space-separated integers si (1≤si≤104) — the sizes of the paintings. The sum of n over all test cases doesn't exceed 2⋅105. Additional constraint on the input: Such an integer w exists for each test case. Please note, that some of the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++). Output For each test case, output a single integer — the value of w which was used to use exactly c squared centimeters of cardboard. Example inputCopy 10 3 50 3 2 1 1 100 6 5 500 2 2 2 2 2 2 365 3 4 2 469077255466389 10000 2023 10 635472106413848880 9181 4243 7777 1859 2017 4397 14 9390 2245 7225 7 176345687772781240 9202 9407 9229 6257 7743 5738 7966 14 865563946464579627 3654 5483 1657 7571 1639 9815 122 9468 3079 2666 5498 4540 7861 5384 19 977162053008871403 9169 9520 9209 9013 9300 9843 9933 9454 9960 9167 9964 9701 9251 9404 9462 9277 9661 9164 9161 18 886531871815571953 2609 10 5098 9591 949 8485 6385 4586 1064 5412 6564 8460 2245 6552 5089 8353 3803 3764 outputCopy 1 2 4 5 7654321 126040443 79356352 124321725 113385729 110961227 Note The first test case is explained in the statement. For the second test case, the chosen w was 2, thus the only cardboard covers an area of c=(2⋅2+6)2=102=100 squared centimeters. For the third test case, the chosen w was 4, which obtains the covered area c=(2⋅4+2)2×5=102×5=100×5=500 squared centimeters. c++实现

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