c语言：输入10个数字，并根据这些数字构造单向链表，之后，再反转链表并打印输出，即A={a1,a2,…,a_n}反转成A={a_n,…,a2,a1} 输入提示: "Please input %d numbers:\n" 输入格式: "%d" 输出格式: "%5d" 程序运行结果实例1： Please input 10 numbers: ↙ 1 2 3 4 5 6 7 8 9 10 10 9 8 7 6 5 4 3 2 1

以下是实现该功能的C语言代码：

#include <stdio.h>
#include <stdlib.h>

// 定义链表节点结构体
struct Node {
    int data;
    struct Node* next;
};

// 反转链表
struct Node* reverseList(struct Node* head) {
    struct Node* prev = NULL;
    struct Node* curr = head;
    while (curr != NULL) {
        struct Node* next = curr->next;
        curr->next = prev;
        prev = curr;
        curr = next;
    }
    return prev;
}

int main() {
    int n = 10;
    printf("Please input %d numbers:\n", n);

    // 构造链表
    struct Node* head = NULL;
    struct Node* tail = NULL;
    for (int i = 0; i < n; i++) {
        int num;
        scanf("%d", &num);
        struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
        newNode->data = num;
        newNode->next = NULL;
        if (head == NULL) {
            head = newNode;
            tail = newNode;
        } else {
            tail->next = newNode;
            tail = newNode;
        }
    }

    // 反转链表
    head = reverseList(head);

    // 打印链表
    printf("Output:\n");
    struct Node* curr = head;
    while (curr != NULL) {
        printf("%5d", curr->data);
        curr = curr->next;
    }

    return 0;
}

输入示例：

Please input 10 numbers:
1 2 3 4 5 6 7 8 9 10

输出示例：

Output:
   10    9    8    7    6    5    4    3    2    1