读取文件,给定密钥,打印出加密矩阵,将明文生成文件,实现 Playfair 密码的解密算法
时间: 2023-05-20 20:01:47 浏览: 116
很高兴为您解答问题。以下是实现 Playfair 密码的解密算法的代码:
```python
def generate_matrix(key):
# 生成加密矩阵
matrix = []
for c in key:
if c not in matrix and c.isalpha():
matrix.append(c)
for c in "ABCDEFGHIKLMNOPQRSTUVWXYZ":
if c not in matrix:
matrix.append(c)
return matrix
def encrypt(plaintext, key):
# 加密明文
matrix = generate_matrix(key)
ciphertext = ""
for i in range(0, len(plaintext), 2):
if i == len(plaintext) - 1:
plaintext += "X"
if plaintext[i] == plaintext[i+1]:
plaintext = plaintext[:i+1] + "X" + plaintext[i+1:]
row1, col1 = divmod(matrix.index(plaintext[i]), 5)
row2, col2 = divmod(matrix.index(plaintext[i+1]), 5)
if row1 == row2:
ciphertext += matrix[row1*5+(col1+1)%5]
ciphertext += matrix[row2*5+(col2+1)%5]
elif col1 == col2:
ciphertext += matrix[((row1+1)%5)*5+col1]
ciphertext += matrix[((row2+1)%5)*5+col2]
else:
ciphertext += matrix[row1*5+col2]
ciphertext += matrix[row2*5+col1]
return ciphertext
def decrypt(ciphertext, key):
# 解密密文
matrix = generate_matrix(key)
plaintext = ""
for i in range(0, len(ciphertext), 2):
row1, col1 = divmod(matrix.index(ciphertext[i]), 5)
row2, col2 = divmod(matrix.index(ciphertext[i+1]), 5)
if row1 == row2:
plaintext += matrix[row1*5+(col1-1)%5]
plaintext += matrix[row2*5+(col2-1)%5]
elif col1 == col2:
plaintext += matrix[((row1-1)%5)*5+col1]
plaintext += matrix[((row2-1)%5)*5+col2]
else:
plaintext += matrix[row1*5+col2]
plaintext += matrix[row2*5+col1]
return plaintext
# 读取文件
with open("plaintext.txt", "r") as f:
plaintext = f.read().upper().replace("J", "I")
# 给定密钥
key = "PLAYFAIREXAMPLE"
# 打印出加密矩阵
matrix = generate_matrix(key)
for i in range(5):
print(matrix[i*5:i*5+5])
# 将明文生成文件
with open("ciphertext.txt", "w") as f:
f.write(encrypt(plaintext, key))
# 解密密文
with open("ciphertext.txt", "r") as f:
ciphertext = f.read().upper()
plaintext = decrypt(ciphertext, key)
print(plaintext)
```
如果您有任何问题,请随时问我。
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