迷宫问题的A*算法(python实现)

很高兴回答你的问题！迷宫问题的A*算法是一种启发式搜索算法，可以帮助我们寻找两点间最短路径。以下是Python实现代码：

import heapq

def heuristic(a, b):
    return abs(a[0] - b[0]) + abs(a[1] - b[1])

def astar(array, start, goal):
    neighbors = [(0,1),(0,-1),(1,0),(-1,0),(1,1),(1,-1),(-1,1),(-1,-1)]
    close_set = set()
    came_from = {}
    gscore = {start:0}
    fscore = {start:heuristic(start, goal)}
    oheap = []

    heapq.heappush(oheap, (fscore[start], start))

    while oheap:
        current = heapq.heappop(oheap)[1]

        if current == goal:
            data = []
            while current in came_from:
                data.append(current)
                current = came_from[current]
            return data[::-1]

        close_set.add(current)
        for i, j in neighbors:
            neighbor = current[0] + i, current[1] + j
            tentative_g_score = gscore[current] + heuristic(current, neighbor)
            if 0 <= neighbor[0] < array.shape[0]:
                if 0 <= neighbor[1] < array.shape[1]:
                    if array[neighbor[0]][neighbor[1]] == 1:
                        continue
                else:
                    continue
            else:
                continue

            if neighbor in close_set and tentative_g_score >= gscore.get(neighbor, 0):
                continue

            if  tentative_g_score < gscore.get(neighbor, 0) or neighbor not in [i[1]for i in oheap]:
                came_from[neighbor] = current
                gscore[neighbor] = tentative_g_score
                fscore[neighbor] = tentative_g_score + heuristic(neighbor, goal)
                heapq.heappush(oheap, (fscore[neighbor], neighbor))

    return False

if __name__ == '__main__':
    n = int(input("请输入迷宫的大小："))
    maze = []
    for i in range(n):
        maze.append([int(x) for x in input().split()])
    start = tuple(map(int, input("请输入起点坐标(从0开始)：").split()))
    goal = tuple(map(int, input("请输入终点坐标(从0开始)：").split()))
    path = astar(np.array(maze), start, goal)
    print("最短路径为：", path)

请注意，这只是一个基础的A*算法实现。如果你需要更高效或更专业的算法实现，请参考其他资料或专业书籍。希望这个示例代码能够帮助你！