sum = 0for i in range(1, 101, 2): sum += iprint("100以内的奇数和为:", sum)
时间: 2023-12-15 22:06:38 浏览: 70
This code calculates and prints the sum of all odd numbers between 1 and 100.
The first line initializes a variable named "sum" to 0.
The second line sets up a loop using the "range" function, which generates a sequence of numbers starting at 1, ending at 101 (exclusive), and incrementing by 2 each time (i.e. only odd numbers).
Inside the loop, the value of "i" is added to the "sum" variable on each iteration.
Finally, the code prints out the sum using the "print" function, along with a message indicating what the sum represents.
So the output of this code would be: "100以内的奇数和为: 2500" (which means "the sum of odd numbers between 1 and 100 is 2500").
相关问题
Sum=0 for i in range(1,11): if i%2-=0: Sum+=i else.: Sum-二i print(sum)
这段代码存在语法错误,应该是:
```
Sum = 0
for i in range(1, 11):
if i % 2 == 0:
Sum += i
else:
Sum -= i
print(Sum)
```
这段代码的作用是计算1到10之间的整数,如果是偶数则加上该数,如果是奇数则减去该数,最后输出计算结果。输出结果为-5,因为1-2+3-4+5-6+7-8+9-10=-5。
sum=0 for i in range(0,10): if i%2==0: sum-=i else: sum+=i print(sum)
这段代码的作用是计算从0到9的奇数和偶数分别累加或累减后的总和,并打印出总和。具体的实现方法是,定义变量sum并初始化为0,然后用for循环遍历0到9的数字。对于每个数字,如果它是偶数,则将其从sum中减去;如果它是奇数,则将其加到sum中。最后打印出sum的值。根据代码的逻辑,这段代码打印出来的结果应该是-5。