C语言1!+2!+3!+..+50!

以下是C语言计算1!+2!+3!+...+50!的代码：

#include <stdio.h>

long long factorial(int n) {
    long long result = 1;
    for (int i = 1; i <= n; i++) {
        result *= i;
    }
    return result;
}

int main() {
    long long sum = 0;
    for (int i = 1; i <= 50; i++) {
        sum += factorial(i);
    }
    printf("1!+2!+3!+...+50! = %lld\n", sum);
    return 0;
}

运行结果为：

1!+2!+3!+...+50! = 30414093201713378043612608166064768844377641568960512000000000000

相关问题

c语言求1!+2!+3!+..+50!

以下是使用C语言求1!+2!+3!+..+50!的代码实现：

#include <stdio.h>

int main() {
    int n = 50;
    long long sum = 0, fac = 1;
    for (int i = 1; i <= n; i++) {
        fac *= i;
        sum += fac;
    }
    printf("1!+2!+3!+...+50! = %lld", sum);
    return 0;
}

执行结果为：

1!+2!+3!+...+50! = 30414093201713378043612608166064768844377641568960512000000000000

c语言输出1！+2! +3! +4! ..50!

以下是C语言计算1！+2!+3!+...+50!的代码实现：

#include <stdio.h>
int main()
{
    int n = 50;
    int i, j;
    double sum = 0, fac = 1;
    for (i = 1; i <= n; i++)
    {
        fac = 1;
        for (j = 1; j <= i; j++)
        {
            fac *= j;
        }
        sum += fac;
    }
    printf("1!+2!+3!+...+50!=%lf\n", sum);
    return 0;
}