五子棋c语言代码 人机

以下是一个简单的五子棋C语言代码，实现了人机对战的功能：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROW 15
#define COL 15
#define PLAYER 1
#define COMPUTER 2

void init_board(int board[ROW][COL]) {
    int i, j;
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            board[i][j] = 0;
        }
    }
}

void print_board(int board[ROW][COL]) {
    int i, j;
    printf("  ");
    for (i = 0; i < COL; i++) {
        printf("%d ", i);
    }
    printf("\n");
    for (i = 0; i < ROW; i++) {
        printf("%d ", i);
        for (j = 0; j < COL; j++) {
            if (board[i][j] == 0) {
                printf("+ ");
            } else if (board[i][j] == PLAYER) {
                printf("O ");
            } else if (board[i][j] == COMPUTER) {
                printf("X ");
            }
        }
        printf("\n");
    }
}

int is_win(int board[ROW][COL], int player) {
    int i, j, k;
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            if (board[i][j] == player) {
                for (k = 1; k < 5; k++) {
                    if (i + k < ROW && board[i + k][j] == player &&
                        i + k - 4 >= 0 && board[i + k - 1][j] == player &&
                        board[i + k - 2][j] == player && board[i + k - 3][j] == player) {
                        return 1;
                    }
                    if (j + k < COL && board[i][j + k] == player &&
                        j + k - 4 >= 0 && board[i][j + k - 1] == player &&
                        board[i][j + k - 2] == player && board[i][j + k - 3] == player) {
                        return 1;
                    }
                    if (i + k < ROW && j + k < COL && board[i + k][j + k] == player &&
                        i + k - 4 >= 0 && j + k - 4 >= 0 && board[i + k - 1][j + k - 1] == player &&
                        board[i + k - 2][j + k - 2] == player && board[i + k - 3][j + k - 3] == player) {
                        return 1;
                    }
                    if (i + k < ROW && j - k >= 0 && board[i + k][j - k] == player &&
                        i + k - 4 >= 0 && j - k + 4 < COL && board[i + k - 1][j - k + 1] == player &&
                        board[i + k - 2][j - k + 2] == player && board[i + k - 3][j - k + 3] == player) {
                        return 1;
                    }
                }
            }
        }
    }
    return 0;
}

void player_move(int board[ROW][COL]) {
    int x, y;
    printf("请输入您的落子位置(x y): ");
    scanf("%d %d", &x, &y);
    while (board[x][y] != 0) {
        printf("该位置已有棋子，请重新输入(x y): ");
        scanf("%d %d", &x, &y);
    }
    board[x][y] = PLAYER;
}

void computer_move(int board[ROW][COL]) {
    int x, y;
    srand(time(NULL));
    do {
        x = rand() % ROW;
        y = rand() % COL;
    } while (board[x][y] != 0);
    board[x][y] = COMPUTER;
    printf("电脑落子位置: (%d %d)\n", x, y);
}

void game() {
    int board[ROW][COL];
    int player = PLAYER;
    init_board(board);
    print_board(board);
    while (1) {
        if (player == PLAYER) {
            player_move(board);
        } else {
            computer_move(board);
        }
        print_board(board);
        if (is_win(board, player)) {
            printf("%s获胜！\n", player == PLAYER ? "玩家" : "电脑");
            break;
        }
        player = player == PLAYER ? COMPUTER : PLAYER;
    }
}

int main() {
    game();
    return 0;
}