import sympy as sp from sympy import Matrix def mat_simp(A): n, p = A.shape for i in range(n): for j in range(p): A[i, j] = sp.simplify(A[i, j]).expand().simplify() return A def mat(u): n = len(u) M = sp.zeros(n, n) for j in range(n): cj = sp.Matrix([int(i == j) for i in range(n)]) Mcj = cj-2*cj.dot(u)/u.norm()**2*u for i in range(n): M[i, j] = Mcj[i] return M def DecompositionQR(A): n, p = A.shape if n != p or A.det() == 0: raise Exception("Les données ne sont pas correctes") AA = A.copy() O = sp.eye(n) for i in range(n): if not AA[i+1:, i].is_zero_matrix(): B = AA.copy() for j in range(i): B[j, i] = 0 Ci = sp.Matrix([int(k == i) for k in range(n)]) S = mat_simp(mat(Ci-B[:, i:i+1]/B[:, i:i+1].norm())) O = S@O AA = S@AA return O.transpose(), AA A = Matrix([2, 0, 2, 2, 1, 1, 2, 2, 0, 1, 1, 2, 0, 0, 2, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]).reshape(5, 5) DecompositionQR(A)怎么修改

这个错误可能是因为 `is_zero_matrix` 方法被误用了。在这里，这个方法应该是用来检查一个矩阵是否为零矩阵的。可以将 `not AA[i+1:, i].is_zero_matrix():` 替换为 `not AA[i+1:, i].is_all_zeros():`。`is_all_zeros()` 方法可以检查一个矩阵的所有元素是否都为零。修改后的代码如下：

import sympy as sp
from sympy import Matrix

def mat_simp(A):
    n, p = A.shape
    for i in range(n):
        for j in range(p):
            A[i, j] = sp.simplify(A[i, j]).expand().simplify()
    return A

def mat(u):
    n = len(u)
    M = sp.zeros(n, n)
    for j in range(n):
        cj = sp.Matrix([int(i == j) for i in range(n)])
        Mcj = cj-2*cj.dot(u)/u.norm()**2*u
        for i in range(n):
            M[i, j] = Mcj[i]
    return M

def DecompositionQR(A):
    n, p = A.shape
    if n != p or A.det() == 0:
        raise Exception("Les données ne sont pas correctes")
    AA = A.copy()
    O = sp.eye(n)
    for i in range(n):
        if not AA[i+1:, i].is_all_zeros():
            B = AA.copy()
            for j in range(i):
                B[j, i] = 0
            Ci = sp.Matrix([int(k == i) for k in range(n)])
            S = mat_simp(mat(Ci-B[:, i:i+1]/B[:, i:i+1].norm()))
            O = S@O
            AA = S@AA
    return O.transpose(), AA

A = Matrix([2, 0, 2, 2, 1, 1, 2, 2, 0, 1, 1, 2, 0, 0, 2, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]).reshape(5, 5)
DecompositionQR(A)

请注意，这只是一个修改建议，并不能保证这个修改能够完全解决问题，因为我并没有完整的代码和数据来进行测试。