使用c语言的知识完成:一元多项式的单链表表示及其运算 (1)采用单链表存储结构,设计并实现一元多式项的表示及其创建、输出、相加、相减等操作。 (2)针对所选择的求解问题,编写测试程序,并选取适当的测试数据,通过运行结果验证算法和程序设计的正确性。
时间: 2024-10-13 18:13:37 浏览: 32
数据结构(C语言)用单链表存储一元多项式并实现两个多项式的相加运算.doc
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在C语言中,我们可以使用结构体和指针来表示一元多项式。首先,定义一个`Term`结构体,包含系数`coefficient`和指数`exponent`:
```c
typedef struct Term {
double coefficient;
int exponent;
} Term;
// 创建一个新的term节点
Term* createTerm(double c, int e) {
Term* newTerm = (Term*)malloc(sizeof(Term));
if (newTerm != NULL) {
newTerm->coefficient = c;
newTerm->exponent = e;
}
return newTerm;
}
// 输出一个term
void printTerm(Term* t) {
printf("Coefficient: %lf, Exponent: %d\n", t->coefficient, t->exponent);
}
// 单链表表示多项式
typedef struct Polynomial {
Term* head;
int size;
} Polynomial;
// 创建空多项式
Polynomial* createPolynomial() {
Polynomial* poly = (Polynomial*)malloc(sizeof(Polynomial));
poly->head = NULL;
poly->size = 0;
return poly;
}
// 添加term到多项式
void addTerm(Polynomial* poly, Term* term) {
if (poly->head == NULL) {
poly->head = term;
} else {
Term* current = poly->head;
while (current->next != NULL && current->exponent < term->exponent) {
current = current->next;
}
if (current->exponent > term->exponent) {
term->next = current->next;
current->next = term;
} else {
term->next = NULL;
current->next = term;
}
}
poly->size++;
}
```
接下来,我们实现多项式的加法和减法:
```c
// 加法:两个多项式的和
Polynomial* addPolynomials(Polynomial* poly1, Polynomial* poly2) {
Polynomial* result = createPolynomial();
Term* current1 = poly1->head, *current2 = poly2->head;
while (current1 != NULL || current2 != NULL) {
if (current1 != NULL && (current2 == NULL || current1->exponent < current2->exponent)) {
addTerm(result, current1);
current1 = current1->next;
} else if (current1 != NULL && current1->exponent > current2->exponent) {
current2 = current2->next;
} else {
// 如果两个term的指数相等,则计算它们的系数之差作为新的term
double diff_coeff = current1->coefficient - current2->coefficient;
addTerm(result, createTerm(diff_coeff, current1->exponent));
current1 = current1->next;
current2 = current2->next;
}
}
return result;
}
// 减法:第一个多项式减去第二个多项式
Polynomial* subtractPolynomials(Polynomial* poly1, Polynomial* poly2) {
Polynomial* result = createPolynomial();
Term* current1 = poly1->head, *current2 = poly2->head;
while (current1 != NULL || current2 != NULL) {
if (current1 != NULL && (current2 == NULL || current1->exponent < current2->exponent)) {
addTerm(result, current1);
current1 = current1->next;
} else if (current1 != NULL && current1->exponent > current2->exponent) {
current2 = current2->next;
} else {
// 如果两个term的指数相等,则计算它们的系数之差作为新的term
double diff_coeff = current1->coefficient - current2->coefficient;
if (diff_coeff >= 0) {
addTerm(result, createTerm(diff_coeff, current1->exponent));
}
current1 = current1->next;
current2 = current2->next;
}
}
// 如果poly2有剩余未处理的term,需要添加负数版本
if (current2 != NULL) {
for (; current2 != NULL; current2 = current2->next) {
addTerm(result, createTerm(-current2->coefficient, current2->exponent));
}
}
return result;
}
```
最后,你可以编写测试函数来验证这些功能:
```c
int main() {
Polynomial* poly1 = createPolynomial();
Polynomial* poly2 = createPolynomial();
// 添加测试项...
// 测试addTerm()
// 测试printPolynomial()
Polynomial* sum = addPolynomials(poly1, poly2);
printPolynomial(sum);
Polynomial* diff = subtractPolynomials(poly1, poly2);
printPolynomial(diff);
freePolygons(&poly1, &poly2, &sum, &diff); // 自定义的释放多项式链表的函数
return 0;
}
```
注意,这只是一个简化的示例,实际项目中可能还需要考虑更全面的错误处理和边界条件检查。
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