a=int(input()) n=0 for m in a: n+=a**2 print(a)
时间: 2024-06-01 09:10:05 浏览: 18
This code is not properly indented and has some syntax errors. Here is a corrected version:
a = int(input())
n = 0
for m in range(a):
n = a ** 2
print(a)
This code prompts the user to input an integer value for a. Then, it initializes a variable n to 0 and starts a for loop that iterates over the range from 0 to a-1 (inclusive). In each iteration, it sets n to the square of a. Finally, it prints the value of a. However, the value of n is never used or printed.
相关问题
abcd= int(input('')) for n in range[0,5]: if abcd=a**4+b**4+c**4+d**4: print(n)
这段代码有一些语法错误。正确的代码应该是:
```
abcd = int(input(''))
for n in range(0, 5):
a = n // 1000 % 10
b = n // 100 % 10
c = n // 10 % 10
d = n % 10
if abcd == a**4 + b**4 + c**4 + d**4:
print(n)
```
这段代码的作用是,给定一个四位数 abcd,找出所有满足 a^4+b^4+c^4+d^4=abcd 的四位数 n。
n=int(input()) for i in range(1,n+1): a=2**(i-1) s=0 s=s+a print(s)
There seems to be a syntax error in the code. Here's a corrected version:
n = int(input())
for i in range(1, n+1):
a = 2**(i-1)
s = 0
s += a
print(s)
This code will print a sequence of powers of 2 starting from 1 up to 2^(n-1), where n is the input number. For example, if n=5, the output will be:
1
2
4
8
16
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