Input a 4*3 table, calculate the sum of each row.c
时间: 2024-03-26 14:42:28 浏览: 83
Sure, here is a Python code that can calculate the sum of each row in a 4*3 table:
```python
table = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
[10, 11, 12]]
row_sums = []
for row in table:
row_sum = sum(row)
row_sums.append(row_sum)
print(row_sums)
```
Output:
```
[6, 15, 24, 33]
```
In the above code, `table` is a 4*3 table (a list of lists) with 4 rows and 3 columns. We then iterate over each row in the table, calculate the sum of the row using the `sum()` function, and append the row sum to a new list called `row_sums`. Finally, we print out the `row_sums` list, which contains the sum of each row in the table.
相关问题
Input a 4*3 table, calculate the sum of each row. Inut: 12 integers in 4*3 tabel Output: 4 integers with each one in single line.c语言实现
好的,以下是C语言实现的代码:
```c
#include <stdio.h>
int main()
{
int table[4][3]; // 定义4*3的表格
int sum[4] = {0}; // 定义每行的和,初始值为0
// 读入表格
for (int i = 0; i < 4; i++)
{
for (int j = 0; j < 3; j++)
{
scanf("%d", &table[i][j]);
sum[i] += table[i][j]; // 计算每行的和
}
}
// 输出每行的和
for (int i = 0; i < 4; i++)
{
printf("%d\n", sum[i]);
}
return 0;
}
```
这个程序先定义了一个4*3的表格和一个长度为4的数组,用于存储每行的和。然后通过循环读入表格中的12个整数,并计算每行的和。最后再循环输出每行的和即可。
Input a 4*3 table,calculate the sum of each row. Inut:12 integers in 4*3 tabel Output:4 integers with each one in sibgle line,用c语言回答
好的,针对您的问题,以下是C语言的代码实现:
```c
#include <stdio.h>
int main() {
int table[4][3];
int row_sum[4] = {0};
// Input the table
printf("Please input the 4*3 table:\n");
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 3; j++) {
scanf("%d", &table[i][j]);
row_sum[i] += table[i][j];
}
}
// Output the row sum
printf("The sum of each row is:\n");
for (int i = 0; i < 4; i++) {
printf("%d\n", row_sum[i]);
}
return 0;
}
```
以上代码中,我们首先定义了一个 4*3 的二维数组 table,用于存储输入的表格数据。同时,我们还定义了一个长度为 4 的数组 row_sum,用于存储每一行的和。然后,我们通过双重循环读入表格数据,并计算每一行的和,最后输出每一行的和即可。
希望以上代码能够帮到您!
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