编程序找出N之内的所有完数，并按下面格式输出其因子 C++输出? its factors are ? ? ?

以下是用 C++ 编写的程序，可以找出 N 以内的所有完数，并按照要求输出：

#include <iostream>
#include <vector>

using namespace std;

vector<int> get_factors(int num) {
    vector<int> factors;
    for (int i = 1; i < num; i++) {
        if (num % i == 0) {
            factors.push_back(i);
        }
    }
    return factors;
}

int main() {
    int n;
    cout << "Enter a number N: ";
    cin >> n;

    for (int i = 1; i <= n; i++) {
        vector<int> factors = get_factors(i);
        int sum_of_factors = 0;
        for (int factor : factors) {
            sum_of_factors += factor;
        }
        if (i == sum_of_factors) {
            cout << i << " is a perfect number, its factors are: ";
            for (int factor : factors) {
                cout << factor << " ";
            }
            cout << endl;
        }
    }

    return 0;
}

运行程序后，输入一个正整数 N，程序会找出 1 到 N 之间的所有完数，并输出其因子，输出格式符合要求。