verilog8位计数器
时间: 2023-10-17 07:05:48 浏览: 43
根据提供的引用资料,这是一个Verilog的8位计数器的示例代码:
```verilog
module count( clk, rst_n, count_out );
input clk;
input rst_n;
output reg [7:0 count_out;
always @ ( posedge clk or negedge rst_n ) begin
if( !rst_n ) begin
count_out <= 8'b0;
end else begin
count_out <= count_out + 1'b1;
end
end
endmodule
```
这个计数器的原理是在时钟上升沿时,输出信号从0开始,每个时钟周期输出值加1。当复位信号有效时,输出被清零。计时实现只需累加即可。计数器在许多场合都有应用,比如产生ROM地址、分频、状态机等。
对于这个计数器的激励信号,可以使用以下代码进行编写:
```verilog
`timescale 1 ns/ 1 ps
module count_vt();
reg clk;
reg rst_n;
wire [7:0 count_out;
count i1 ( .clk(clk), .count_out(count_out), .rst_n(rst_n) );
initial begin
clk = 0;
rst_n = 0;
#20;
rst_n = 1;
#600;
$stop;
$display("Running testbench");
end
always begin
#5
clk = ~clk;
end
endmodule
```
这个激励信号在初始化时会给clk和rst_n赋初值,并通过时钟变换信号clk来模拟时钟的上升沿。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
- *1* *2* *3* [Quartus ii 与 Verilog入门教程(1)——Verilog实现8位计数器](https://blog.csdn.net/DengFengLai123/article/details/105335836)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 100%"]
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