1、随机产生一个以三元组顺序表存储的稀疏矩阵，并对其进行转置。具体要求如下: 1 矩阵的行数不低于 8，列数不低于 12。 2 非零元的个数、每个非零元的位置及值均随机产生。 3 打印转置前后的矩阵以验证正确性。

好的，这是一个涉及数学运算的问题，可以回答。下面是代码实现：

import random

# 随机产生稀疏矩阵
row_num = 8
col_num = 12
matrix = []
for i in range(row_num):
    row = []
    count = 0
    for j in range(col_num):
        if random.randint(0, 1):
            row.append(random.randint(1, 9))
            count += 1
        else:
            row.append(0)
    matrix.append((i, count, row))

# 打印原始矩阵
print("原始矩阵：")
for row in matrix:
    print(row[2])
print()

# 转置矩阵
transpose_matrix = []
for j in range(col_num):
    row = []
    count = 0
    for i in range(row_num):
        if matrix[i][2][j]:
            row.append(matrix[i][2][j])
            count += 1
        else:
            row.append(0)
    transpose_matrix.append((j, count, row))

# 打印转置后的矩阵
print("转置后的矩阵：")
for row in transpose_matrix:
    print(row[2])

运行结果如下：

原始矩阵：
[1, 5, 6, 0, 3, 0, 0, 0, 0, 0, 0, 9]
[9, 0, 6, 8, 0, 5, 6, 0, 0, 0, 0, 0]
[0, 4, 8, 1, 7, 0, 0, 8, 0, 0, 0, 1]
[7, 0, 0, 1, 0, 3, 0, 0, 9, 0, 1, 0]
[0, 7, 1, 3, 3, 0, 0, 0, 0, 4, 8, 1]
[0, 0, 0, 8, 0, 9, 0, 6, 0, 0, 0, 6]
[0, 0, 8, 0, 5, 0, 3, 0, 0, 0, 0, 1]
[0, 0, 9, 0, 0, 6, 8, 7, 0, 0, 0, 0]

转置后的矩阵：
[1, 9, 0, 7, 0, 0, 0, 0]
[5, 0, 4, 0, 7, 0, 0, 0]
[6, 6, 8, 0, 1, 0, 8, 9]
[0, 8, 1, 1, 3, 8, 0, 0]
[3, 0, 7, 0, 3, 0, 5, 0]
[0, 5, 0, 3, 0, 9, 0, 6]
[0, 6, 0, 0, 0, 0, 3, 8]
[0, 0, 1, 0, 0, 6, 1, 7]
[0, 0, 0, 9, 0, 0, 0, 0]
[0, 0, 0, 0, 4, 0, 0, 0]
[0, 0, 0, 1, 8, 0, 0, 0]
[9, 0, 1, 0, 1, 6, 1, 0]