Assume you have four datasets: "employees", "departments", "projects", and "assignments". The scheme of these databases are as follows: The "employees" dataset contains employee information including a unique "employee_ID", "employee_name", and "department_ID". The "departments" dataset contains department information including a unique "department_ID" and "department_name". The "projects" dataset contains project information including a unique "project_ID", "project_name", and "department_ID". The "assignments" dataset contains information about which employees are assigned to which projects, including the "employee_ID" and "project_ID" associated with each assignment. Write a SQL query to retrieve the name and department of all employees who are assigned to a project that is not in the same department as their own department.

时间: 2023-07-06 16:35:51 浏览: 94
Here's a SQL query to retrieve the name and department of all employees who are assigned to a project that is not in the same department as their own department: ``` SELECT e.employee_name, d.department_name FROM employees e INNER JOIN assignments a ON e.employee_ID = a.employee_ID INNER JOIN projects p ON a.project_ID = p.project_ID INNER JOIN departments d ON e.department_ID = d.department_ID WHERE p.department_ID <> e.department_ID; ``` In this query, we are joining the "employees", "assignments", "projects", and "departments" datasets to retrieve the necessary information. We are selecting the "employee_name" and "department_name" columns from the "employees" and "departments" tables, respectively. Then we are using INNER JOINs to join the tables based on their corresponding IDs. Finally, we are adding a WHERE clause to filter the results and only show employees who are assigned to a project that is not in the same department as their own department. This is done by comparing the "department_ID" column in the "projects" table with the "department_ID" column in the "employees" table.
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用c++解决Several currency exchange points are working in our city. Let us suppose that each point specializes in two particular currencies and performs exchange operations only with these currencies. There can be several points specializing in the same pair of currencies. Each point has its own exchange rates, exchange rate of A to B is the quantity of B you get for 1A. Also each exchange point has some commission, the sum you have to pay for your exchange operation. Commission is always collected in source currency. For example, if you want to exchange 100 US Dollars into Russian Rubles at the exchange point, where the exchange rate is 29.75, and the commission is 0.39 you will get (100 - 0.39) * 29.75 = 2963.3975RUR. You surely know that there are N different currencies you can deal with in our city. Let us assign unique integer number from 1 to N to each currency. Then each exchange point can be described with 6 numbers: integer A and B - numbers of currencies it exchanges, and real RAB, CAB, RBA and CBA - exchange rates and commissions when exchanging A to B and B to A respectively. Nick has some money in currency S and wonders if he can somehow, after some exchange operations, increase his capital. Of course, he wants to have his money in currency S in the end. Help him to answer this difficult question. Nick must always have non-negative sum of money while making his operations. Input The first line contains four numbers: N - the number of currencies, M - the number of exchange points, S - the number of currency Nick has and V - the quantity of currency units he has. The following M lines contain 6 numbers each - the description of the corresponding exchange point - in specified above order. Numbers are separated by one or more spaces. 1 ≤ S ≤ N ≤ 100, 1 ≤ M ≤ 100, V is real number, 0 ≤ V ≤ 103. For each point exchange rates and commissions are real, given with at most two digits after the decimal point, 10-2 ≤ rate ≤ 102, 0 ≤ commission ≤ 102. Let us call some sequence of the exchange operations simple if no exchange point is used more than once in this sequence. You may assume that ratio of the numeric values of the sums at the end and at the beginning of any simple sequence of the exchange operations will be less than 104. Output If Nick can increase his wealth, output YES, in other case output NO.

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