用c++解决Several currency exchange points are working in our city. Let us suppose that each point specializes in two particular currencies and performs exchange operations only with these currencies. There can be several points specializing in the same pair of currencies. Each point has its own exchange rates, exchange rate of A to B is the quantity of B you get for 1A. Also each exchange point has some commission, the sum you have to pay for your exchange operation. Commission is always collected in source currency. For example, if you want to exchange 100 US Dollars into Russian Rubles at the exchange point, where the exchange rate is 29.75, and the commission is 0.39 you will get (100 - 0.39) * 29.75 = 2963.3975RUR. You surely know that there are N different currencies you can deal with in our city. Let us assign unique integer number from 1 to N to each currency. Then each exchange point can be described with 6 numbers: integer A and B - numbers of currencies it exchanges, and real RAB, CAB, RBA and CBA - exchange rates and commissions when exchanging A to B and B to A respectively. Nick has some money in currency S and wonders if he can somehow, after some exchange operations, increase his capital. Of course, he wants to have his money in currency S in the end. Help him to answer this difficult question. Nick must always have non-negative sum of money while making his operations. Input The first line contains four numbers: N - the number of currencies, M - the number of exchange points, S - the number of currency Nick has and V - the quantity of currency units he has. The following M lines contain 6 numbers each - the description of the corresponding exchange point - in specified above order. Numbers are separated by one or more spaces. 1 ≤ S ≤ N ≤ 100, 1 ≤ M ≤ 100, V is real number, 0 ≤ V ≤ 103. For each point exchange rates and commissions are real, given with at most two digits after the decimal point, 10-2 ≤ rate ≤ 102, 0 ≤ commission ≤ 102. Let us call some sequence of the exchange operations simple if no exchange point is used more than once in this sequence. You may assume that ratio of the numeric values of the sums at the end and at the beginning of any simple sequence of the exchange operations will be less than 104. Output If Nick can increase his wealth, output YES, in other case output NO.

c++钱的问题

Sahana.rar_face_face detection_fortbbd_suppose3hr

用c++代码实现。Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 French fran

以下是C++代码实现： c++ #include #include #include using namespace std; const int N = 210; int n, m; double dist[N][N]; int main() { while (cin >> n, n) { memset(dist, 0, sizeof dist); // ...

(Geometry: intersecting point) Suppose two line segments intersect. The two end-points for the first line segment are (x1, y1) and (x2, y2) and for the second line segment are (x3, y3) and (x4, y4).Write a program that prompts the user to enter these four endpoints and displays the intersecting point. the intersecting point can be found by solving a linear equation. Write the LinearEquation class in Programming to solve this equation. input style : Enter eight double number output style: Displays the intersecting point or The two lines are parallel

The isParallel method checks if the two lines are parallel by comparing the slopes of the two lines, and the getX and getY methods solve the system of two linear equations for the intersecting ...

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a different permutation. Check to see the result if we double it again! Now you are suppose to check if there are more numbers with this property. That is, double a given number with k digits, you are to tell if the resulting number consists of only a permutation of the digits in the original number. Input Specification: Each input contains one test case. Each case contains one positive integer with no more than 19 digits. Output Specification: For each test case, first print in a line "Yes" if doubling the input number gives a number that consists of only a permutation of the digits in the original number, or "No" if not. Then in the next line, print the doubled number. Sample Input: 1234567899 Sample Output: Yes 2469135798

首先，我们需要将输入的数转换成字符串，并计算出它的长度。接着，我们将该数乘以2，再将结果转换成字符串，并且将它的长度与原始字符串的长度进行比较。如果长度不同，那么乘以2得到的数字肯定不是原始数字的排列。...

Recall that an exponential random variable 𝑋~exp (𝜆) has mean 𝜆 1 and pdf given by: 𝑓(𝑥) = 𝜆𝑒 −𝜆𝑥 on 𝑥 ≥ 0. (b) Suppose that 𝑋1 and 𝑋2 are independent exponential random variables with mean 𝜆 1 . Let 𝑇 = min (𝑋1 ,𝑋2 ). Find the cdf of 𝑇. (Hint: what is 𝑃(𝑇 ≥ 𝑡)?)教我怎么做

首先，我们可以使用下面的公式计算 $P(T \geq t)$： $$P(T \geq t) = P(X_1 \geq t, X_2 \geq t)$$ 因为 $X_1$ 和 $X_2$ 是独立的，所以我们可以将概率分解为： $$P(X_1 \geq t, X_2 \geq t) = P(X_1 \geq t) \...

Write a C++ program that implements flipping the contents of each line of a string in a text file and outputs the flipped result to another text file. Both the input file name and output file name are specified by the user. Example: Suppose the input file input.txt has the following contents: Hello, world! Welcome to C++! After executing the program, the output file output.txt should contain the following contents: !dlrow ,olleH !++C ot emocleW Tip: You can use the getline() function to read the string from the input file line by line, then use the reverse() function to flip the string, and finally write the flipped string to the output file.

Sure, here's a C++ program that implements flipping the contents of each line of a string in a text file and outputs the flipped result to another text file: cpp #include #include #include #...

We show that every atom a that is added to C by the algorithm is a logical consequence of KB ∪ Percepts. Suppose there is an atom h ∈ C that is not a logical consequence. Let h be the first ever such atom to be added in C. There must be some clause in KB ∪ Percepts, in the form h ← a1 ∧ · · · ∧ am such that a1, . . . , am are all in C. By assumption, KB ∪ Percepts |= ai for all 1 ≤ i ≤ m. Then it must be that KB ∪ Percepts |= h. Contradiction.是什么意思

这段文字描述了一个关于知识库（KB）和感知（Percepts）的算法，在该算法中，每个添加到集合C中的原子a都是KB和Percepts的逻辑结果。如果有一个原子h在C中，但不是它们的逻辑结果，那么假设h是第一个这样的原子被...

用C++编写程序，实现以下问题2、题目ID Codes（POJ1146） Time Limit: 1000MS Memory Limit: 10000K 描述： It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical measure--all citizens are to have a tiny microcomputer surgically implanted in their left wrists. This computer will contains all sorts of personal information as well as a transmitter which will allow people's movements to be logged and monitored by a central computer. (A desirable side effect of this process is that it will shorten the dole queue for plastic surgeons.) An essential component of each computer will be a unique identification code, consisting of up to 50 characters drawn from the 26 lower case letters. The set of characters for any given code is chosen somewhat haphazardly. The complicated way in which the code is imprinted into the chip makes it much easier for the manufacturer to produce codes which are rearrangements of other codes than to produce new codes with a different selection of letters. Thus, once a set of letters has been chosen all possible codes derivable from it are used before changing the set. For example, suppose it is decided that a code will contain exactly 3 occurrences of a', 2 of b' and 1 of c', then three of the allowable 60 codes under these conditions are: abaabc abaacb ababac These three codes are listed from top to bottom in alphabetic order. Among all codes generated with this set of characters, these codes appear consecutively in this order. Write a program to assist in the issuing of these identification codes. Your program will accept a sequence of no more than 50 lower case letters (which may contain repeated characters) and print the successor code if one exists or the message No Successor' if the given code is the last in the sequence for that set of characters. 输入： Input will consist of a series of lines each containing a string representing a code. The entire file will be terminated by a line consisting of a single #. 输出： Output will consist of one line for each code read containing the successor code or the words 'No Successor'. 样例输入 abaacb cbbaa # 样例输出 ababac No Successor

以下是使用C++编写的程序，可以解决该问题： c++ #include #include #include using namespace std; int main() { char str[55]; while(cin >> str && str[0] != '#') { if(next_permutation(str, str +...

为下面题目写出详细证明推到过程Suppose that Xt and Yt are independent Poisson processes with parameter 1 and 2 respectively measuring the number of calls arriving at two different service center. Let Zt = Xt + Yt (1) Find the distribution of Zt (2) Derive the distribution of Zt+s − Zs (3) Is Zt+s − Zs independent of Zs? Why.

(1) The distribution of Zt can be found by considering that it is the sum of two independent Poisson processes with parameters 1 and 2 respectively. The probability mass function of a Poisson process ...

(a) Consider the case of a European Vanilla Call option which is path independent. Examine the convergence of the Monte Carlo Method using the programme given in ‘MC Call.m’. How does the error vary with the number of paths nP aths? The current time is t = 0 and the Expiry date of the option is t = T = 0.5. Suppose that the current value of the underlying asset is S(t = 0) = 100 and the Exercise price is E = 100, with a risk free interest rate of r = 0.04 and a volatility of σ = 0.5. (b) Now repeat part (a) above but assume that the volatility is σ = 0.05. Does the change in the volatility σ influence the convergence of the Monte Carlo Method? (c) Now repeat part (a) but instead of taking one big step from t = 0 to t = T divide the interval into nSteps discrete time steps by using the programme given in ‘MC Call Small Steps.m’. Confirm that for path independent options, the value of nP aths determines the rate of convergence and that the value of nSteps can be set to 1. (d) Now let us consider path dependent options. The programme given in ‘MC Call Small Steps.m’ is the obvious starting point here. We assume that the current time is t = 0 and the expiry date of the option is t = T = 0.5. The current value of the underlying asset is S(t = 0) = 100 and the risk free interest rate is r = 0.05 and the volatility is σ = 0.3. (i) Use the Monte Carlo Method to estimate the value of an Arithematic Average Asian Strike Call option with Payoff given by max(S(T) − S, ¯ 0). (ii) Use the Monte Carlo Method to estimate the value of an Up and Out Call option with Exercise Price E = 100 and a barrier X = 150. (iii) Comment on the the rate of convergence for part (i) and (ii) above with respect to the parameters nP aths and nP aths使用matlab编程

In part (i), an arithmetic average Asian strike call option is being valued, while in part (ii), an up and out call option is being valued. The rate of convergence for these options depends on both ...

.Let color be the following structure: struct color int red;int green;int blue;};Suppose the resolution of the picture is 300 x 300 that is, you need to create a two-dimensional array of 300 x 300 pixels, each of which stores information in three channels: red, green, and blue. The color value is a random integer.

To create a two-dimensional array of 300 x 300 pixels, each storing information in the three color channels, we can use the following code in C++: struct color { int red; int green; int blue; ...

For example, suppose we have four solutions in Q as shown in Table 2. Each solution has a label and a membership degree with respect to the positive class predicted by the classifier. When the accuracy of the classifier is larger than or equal to 70%, these solutions are ranked in descending order with respect to their membership degrees (i.e., s2 > s3 > s1 > s4). When the accuracy of the classifier is larger than or equal to 30% and smaller than 70%, the positive solutions are ranked in ascending order with respect to their membership degrees (i.e., s3 > s2). Next, the negative solutions are ranked in descending order with respect to their membership degrees (i.e., s1 > s4). Then, the positive solutions are ranked before the negative solutions (i.e., s3 > s2 > s1 > s4). When the accuracy of the classifier is smaller than 30%, these solutions are ranked in ascending order with respect to their membership degrees (i.e., s4 > s1 > s3 > s2).

这段文字描述了一个在分类器准确率不同范围内如何对解决方案进行排名的过程。其中，每个解决方案都有一个标签和一个属于正类的隶属度。当分类器准确率大于等于70%时，这些解决方案按照隶属度从大到小排名。当分类器...

1） Inheritance：Suppose there is a base class Animal that has a name property and an eat() method. Now there are two derived classes Cat and Dog, both of which inherit from the Animal class. The Cat class has a catchMouse() method and the Dog class has a bark() method. Write the main() function that does the following: create a Cat object and a Dog object; assign values to their name properties, respectively; call the eat() and catchMouse() methods of the Cat object; call the eat() and bark() methods of the Dog object. 2）Polymorphism： Based on 1), add a virtual function speak() in the base class Animal to represent the behavior of animals making sounds. The two derived classes Dog and Cat implement the speak() function respectively, and output "Wow Woof Woof" and "Meow Meow Meow" respectively. Please define a pointer to the Animal object in the main function, let it point to the Dog object and the Cat object, and call their speak() function. Submit your completed program as a single C++ source file.

In the main() function, we define a pointer to an Animal object, and we use it to point to both a Cat object and a Dog object. We then call the speak() function through the pointer, and ...

分 Suppose the hard disk with SCAN scheduling Alg has a single platter （盘面） as illustrated below , and the rotation speed for the platter is 6000 rounds per minute . The disk has only 200 tracks , and each track is composed of 100 sectors . The time cost for the disk arm to navigate between neighboring track is about 1ms. Suppose the disk arm currently hangs over the 100th track , and moves centrifugally towards lower - order tracks on the outside . The pending disk block requests are positioned on the tracks with numbers 50, 180,90,30,120, respectively , and form a queue . For each block in this queue , we do not know what are its exact sector numbers , and we can only assume that the corresponding sector randomly distributes on each track as shown below . Then , The expected time to finish the retrieval of the five sectors is1] ms . If SSTF is used , the expected time is [] ms . 0 磁道磁头运动方向 .

根据题目所描述的情况，我们可以计算出使用 SCAN 调度算法时，磁头移动的距离为： - 从 100 磁道移动到 50 磁道，需要移动 50 个磁道，耗时 50ms； - 从 50 磁道移动到 30 磁道，需要移动 20 个磁道，耗时 20ms； -...

Consider+a+circuit-switched+network.+Suppose+that+all+links+in+the+network+use+TDM+with+10+slots+and

In the given scenario, let's assume that all links in the network use Time Division Multiplexing (TDM) with 10 slots. TDM is a technique that allows multiple signals to be transmitted simultaneously ...

Objectives: To practice File and text input output concept 1. (Process scores in a text file) Suppose a text file contains an unspecified number of scores separated by spaces. Write a program that prompts the user to enter the file, reads the scores from the file, and displays their total and average. 2. (Write/read data) Write a program to create a file named Lab07_02.txt if it does not exist. Write 100 integers created randomly into the file using text I/O. Integers are separated by spaces in the file. Read the data back from the file and display the data in increasing order. 用JAVA解答

Scanner input = new Scanner(System.in); System.out.print("Enter the file name: "); String fileName = input.nextLine(); File file = new File(fileName); try { Scanner fileInput = new Scanner(file...

基于net的超市管理系统源代码（完整前后端+sqlserver+说明文档+LW）.zip

功能说明：环境说明：开发软件：VS 2017 （版本2017以上即可，不能低于2017）数据库：SqlServer2008r2（数据库版本无限制，都可以导入）开发模式：mvc。。。

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Sahana.rar_face_face detection_fortbbd_suppose3hr

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