Given a string S, convert all lowercase letters to uppercase letters, and uppercase letters to lowercase letters in it.
时间: 2023-11-22 12:55:39 浏览: 29
这道题可以用 Python 来实现,具体代码如下:
```python
def swap_case(s):
return s.swapcase()
string = "Hello World"
print(swap_case(string)) # 输出 hELLO wORLD
```
其中,`swapcase()` 方法可以实现大小写字母的互换。在这个例子中,我们定义了一个名为 `swap_case()` 的函数,它接受一个字符串作为参数,并返回大小写字母互换后的字符串。最后,我们定义了一个字符串 `string`,并在控制台打印出调用 `swap_case()` 函数后得到的结果。
相关问题
python语句import string lowercase = string.ascii_lowercase uppercase = string.ascii_uppercase
这段 Python 代码的作用是定义了两个变量 `lowercase` 和 `uppercase`,分别赋值为字符串常量 `string.ascii_lowercase` 和 `string.ascii_uppercase`。
`string.ascii_lowercase` 是一个字符串常量,包含了26个小写字母,其值为:`'abcdefghijklmnopqrstuvwxyz'`。
`string.ascii_uppercase` 是一个字符串常量,包含了26个大写字母,其值为:`'ABCDEFGHIJKLMNOPQRSTUVWXYZ'`。
因此,这段代码的作用是定义了两个变量,分别存储了所有的小写字母和大写字母,方便后续在程序中使用。
Implement about, which takes a list of topic words. It returns a function that can be passed to choose as the select argument. The returned function takes a paragraph and returns a boolean indicating whether that paragraph contains any of the words in topic. To make this comparison accurately, you will need to ignore case (that is, assume that uppercase and lowercase letters don't change what word it is) and punctuation. Assume that all words in the topic list are already lowercased and do not contain punctuation.
Sure, I can help you with that.
Here's an implementation of the `about` function you described:
```python
import string
def about(topic):
def contains_topic_word(paragraph):
# Remove punctuation from paragraph
paragraph = paragraph.translate(str.maketrans('', '', string.punctuation))
# Convert paragraph to lowercase
paragraph = paragraph.lower()
# Check if any word in the paragraph is in the topic list
for word in paragraph.split():
if word in topic:
return True
return False
return contains_topic_word
```
This function takes a list of topic words and returns a function that can be passed to the `choose` function's `select` argument. The returned function takes a paragraph and returns a boolean indicating whether that paragraph contains any of the words in the topic list. It removes punctuation from the paragraph, converts it to lowercase, and checks if any word in the paragraph is in the topic list.
Here's an example usage of this function:
```python
topic = ['python', 'programming', 'language']
contains_topic_word = about(topic)
paragraph = "Python is a high-level programming language. It is widely used for web development, scientific computing, data analysis, artificial intelligence, and more."
if contains_topic_word(paragraph):
print("This paragraph is about Python programming language.")
else:
print("This paragraph is not about Python programming language.")
```
Output:
```
This paragraph is about Python programming language.
```
I hope this helps! Let me know if you have any questions.