给定两个均不超过9的正整数a和n,要求编写函数求a+aa+aa --+(n个a)之和。用C语言解决

以下是C语言的代码实现：

#include <stdio.h>

int fn(int a, int n);
int SumA(int a, int n);

int main() {
    int a, n;
    scanf("%d %d", &a, &n);
    printf("fn(%d, %d) = %d\n", a, n, fn(a, n));
    printf("s = %d\n", SumA(a, n));
    return 0;
}

int fn(int a, int n) {
    int i, p = 0;
    for (i = 1; i <= n; i++) {
        p = p * 10 + a;
    }
    return p;
}

int SumA(int a, int n) {
    int i, q = 0;
    for (i = 1; i <= n; i++) {
        q += fn(a, i);
    }
    return q;
}