x3050:x70A4 x70A2: x70A3 x70A3 xFFFF x70A4 x123BAddress X3010: 1110 0110 0011 1111 Address X3011: 0110 1000 1100 0000 Address X3012: 0110 1101 0000 0000 a) Explain what each instruction does. (6 points) b) What is that value to be loaded into R6? (2 points) c) We could replace the three-instruction sequence with a single instruction. What is it? Write the instruction in binary. (2 points)
时间: 2023-06-18 20:06:10 浏览: 110
CRC.rar_CRC CCITT_checksum_crc 16_crc 16 ccitt_x16 x12 x5 1
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a)
- x3050:x70A4: This instruction loads the value at memory address x70A4 into the accumulator (R0).
- x70A2: This instruction moves the value in the accumulator (R0) to register R2.
- x70A3: This instruction moves the value in register R2 to memory address x70A3.
- xFFFF: This instruction does not do anything as it is just a placeholder value.
- x70A4: This instruction moves the value in register R0 to memory address x70A4.
- x123B: This instruction is not an instruction, but rather an address.
b) The value to be loaded into R6 is not given in the provided instructions.
c) We could replace the three-instruction sequence with a single instruction:
Move accumulator (R0) to memory address x70A3 and x70A4 simultaneously.
The binary representation of this instruction would be:
1110 0011 1111 0110 1101 0000 0000
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