Input a 4*3 table, calculate the sum of each row.

Sure, here is a Python code that can calculate the sum of each row in a 4*3 table:

table = [[1, 2, 3],
         [4, 5, 6],
         [7, 8, 9],
         [10, 11, 12]]

row_sums = []
for row in table:
    row_sum = sum(row)
    row_sums.append(row_sum)

print(row_sums)

Output:

[6, 15, 24, 33]

In the above code, `table` is a 4*3 table (a list of lists) with 4 rows and 3 columns. We then iterate over each row in the table, calculate the sum of the row using the `sum()` function, and append the row sum to a new list called `row_sums`. Finally, we print out the `row_sums` list, which contains the sum of each row in the table.

相关问题

Input a 4*3 table, calculate the sum of each row.c

Sure, here is a Python code that can calculate the sum of each row in a 4*3 table:

table = [[1, 2, 3],
         [4, 5, 6],
         [7, 8, 9],
         [10, 11, 12]]

row_sums = []
for row in table:
    row_sum = sum(row)
    row_sums.append(row_sum)

print(row_sums)

Output:

[6, 15, 24, 33]

In the above code, `table` is a 4*3 table (a list of lists) with 4 rows and 3 columns. We then iterate over each row in the table, calculate the sum of the row using the `sum()` function, and append the row sum to a new list called `row_sums`. Finally, we print out the `row_sums` list, which contains the sum of each row in the table.

Input a 4*3 table, calculate the sum of each row. Inut: 12 integers in 4*3 tabel Output: 4 integers with each one in single line.c语言实现

好的，以下是C语言实现的代码：

#include <stdio.h>

int main()
{
    int table[4][3]; // 定义4*3的表格
    int sum[4] = {0}; // 定义每行的和，初始值为0

    // 读入表格
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 3; j++)
        {
            scanf("%d", &table[i][j]);
            sum[i] += table[i][j]; // 计算每行的和
        }
    }

    // 输出每行的和
    for (int i = 0; i < 4; i++)
    {
        printf("%d\n", sum[i]);
    }

    return 0;
}

这个程序先定义了一个4*3的表格和一个长度为4的数组，用于存储每行的和。然后通过循环读入表格中的12个整数，并计算每行的和。最后再循环输出每行的和即可。