codeblocks的C语言围棋双人对战程序包含吃子，计算外气，禁手规则的代码

### 回答1：
以下是一个简单的C语言围棋双人对战程序，包含吃子，计算外气和禁手规则的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define BOARD_SIZE 19

enum Stone { EMPTY, BLACK, WHITE };
enum Result { BLACK_WINS, WHITE_WINS, DRAW, CONTINUE };

struct Position {
    int x, y;
};

struct Move {
    struct Position pos;
    enum Stone stone;
};

struct Board {
    enum Stone grid[BOARD_SIZE][BOARD_SIZE];
    enum Stone next_player;
    int black_captures;
    int white_captures;
};

struct Board* init_board() {
    struct Board* board = malloc(sizeof(struct Board));
    memset(board->grid, EMPTY, sizeof(board->grid));
    board->next_player = BLACK;
    board->black_captures = 0;
    board->white_captures = 0;
    return board;
}

void print_board(struct Board* board) {
    printf("  ");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%c ", 'A' + i);
    }
    printf("\n");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%2d", i + 1);
        for (int j = 0; j < BOARD_SIZE; j++) {
            switch (board->grid[i][j]) {
                case EMPTY:
                    printf("  ");
                    break;
                case BLACK:
                    printf("● ");
                    break;
                case WHITE:
                    printf("○ ");
                    break;
            }
        }
        printf("%2d", i + 1);
        if (i == 3) {
            printf("  Black captures: %d", board->black_captures);
        } else if (i == 4) {
            printf("  White captures: %d", board->white_captures);
        }
        printf("\n");
    }
    printf("  ");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%c ", 'A' + i);
    }
    printf("\n");
}

int is_on_board(struct Position pos) {
    return pos.x >= 0 && pos.x < BOARD_SIZE && pos.y >= 0 && pos.y < BOARD_SIZE;
}

enum Result play_move(struct Board* board, struct Move move) {
    if (board->grid[move.pos.x][move.pos.y] != EMPTY) {
        return CONTINUE;
    }
    board->grid[move.pos.x][move.pos.y] = move.stone;
    if (move.stone == BLACK) {
        board->next_player = WHITE;
    } else {
        board->next_player = BLACK;
    }
    int num_captures = 0;
    struct Position neighbors[4] = { { move.pos.x - 1, move.pos.y }, { move.pos.x + 1, move.pos.y }, { move.pos.x, move.pos.y - 1 }, { move.pos.x, move.pos.y + 1 } };
    for (int i = 0; i < 4; i++) {
        struct Position neighbor = neighbors[i];
        if (!is_on_board(neighbor)) {
            continue;
        }
        if (board->grid[neighbor.x][neighbor.y] == board->next_player) {
            int liberties = 0;
            struct Position visited[BOARD_SIZE * BOARD_SIZE];
            int num_visited = 0;
            int frontier_size = 1;
            struct Position frontier[BOARD_SIZE * BOARD_SIZE];
            frontier[0] = neighbor;
            while (frontier_size > 0) {
                struct Position current = frontier[--frontier_size];
                visited[num_visited++] = current;
                struct Position neighbors[4] = { { current.x - 1, current.y }, { current.x + 1, current.y }, { current.x, current.y - 1 }, { current.x, current.y + 1 } };
                for (int j = 0; j < 4; j++) {
                    struct Position neighbor = neighbors[j];
                    if (!is_on_board(neighbor)) {
                        continue;
                    }
                    if (board->grid[neighbor.x][neighbor.y] == EMPTY) {
                        liberties++;
                    } else if (board->grid[neighbor.x][neighbor.y] == board->next_player) {
                        int visited_already = 0;
                        for (int k = 0; k < num_visited; k++) {
                            if (visited[k].x == neighbor.x && visited[k].y == neighbor.y) {
                                visited_already = 1;
                                break;
                            }
                        }
                        if (!visited_already) {
                            frontier[frontier_size++] = neighbor;
                        }
                    }
                }
            }
            if (liberties == 0) {
                num_captures += num_visited;
                for (int j = 0; j < num_visited; j++) {
                    board->grid[visited[j].x][visited[j].y] = EMPTY;
                }
            }
        }
    }
    if (num_captures > 0) {
        if (move.stone == BLACK) {
            board->black_captures += num_captures;
        } else {
            board->white_captures += num_captures;
        }
    }
    struct Position neighbors[4] = { { move.pos.x - 1, move.pos.y }, { move.pos.x + 1, move.pos.y }, { move.pos.x, move.pos.y - 1 }, { move.pos.x, move.pos.y + 1 } };
    for (int i = 0; i < 4; i++) {
        struct Position neighbor = neighbors[i];
        if (!is_on_board(neighbor)) {
            continue;
        }
        if (board->grid[neighbor.x][neighbor.y] == EMPTY) {
            return CONTINUE;
        }
    }
    struct Position visited[BOARD_SIZE * BOARD_SIZE];
    int num_visited = 0;
    int frontier_size = 1;
    struct Position frontier[BOARD_SIZE * BOARD_SIZE];
    frontier[0] = move.pos;
    while (frontier_size > 0) {
        struct Position current = frontier[--frontier_size];
        visited[num_visited++] = current;
        struct Position neighbors[4] = { { current.x - 1, current.y }, { current.x + 1, current.y }, { current.x, current.y - 1 }, { current.x, current.y + 1 } };
        for (int i = 0; i < 4; i++) {
            struct Position neighbor = neighbors[i];
            if (!is_on_board(neighbor)) {
                continue;
            }
            if (board->grid[neighbor.x][neighbor.y] == board->next_player) {
                int visited_already = 0;
                for (int j = 0; j < num_visited; j++) {
                    if (visited[j].x == neighbor.x && visited[j].y == neighbor.y) {
                        visited_already = 1;
                        break;
                    }
                }
                if (!visited_already) {
                    frontier[frontier_size++] = neighbor;
                }
            } else if (board->grid[neighbor.x][neighbor.y] == EMPTY) {
                return CONTINUE;
            }
        }
    }
    if (move.stone == BLACK) {
        return BLACK_WINS;
    } else {
        return WHITE_WINS;
    }
}

int parse_move(char* input, struct Move* move) {
    if (input[0] == 'p') {
        move->stone = BLACK;
    } else if (input[0] == 'P') {
        move->stone = WHITE;
    } else {
        return 0;
    }
    move->pos.x = input[1] - '1';
    move->pos.y = input[2] - 'A';
    return 1;
}

int is_ko(struct Board* board, struct Move move) {
    if (board->grid[move.pos.x][move.pos.y] != EMPTY) {
        return 0;
    }
    struct Board* board_copy = malloc(sizeof(struct Board));
    memcpy(board_copy, board, sizeof(struct Board));
    enum Result result = play_move(board_copy, move);
    if (result != CONTINUE) {
        free(board_copy);
        return 0;
    }
    for (int i = 0; i < BOARD_SIZE; i++) {
        for (int j = 0; j < BOARD_SIZE; j++) {
            if (board->grid[i][j] != board_copy->grid[i][j]) {
                free(board_copy);
                return 0;
            }
        }
    }
    free(board_copy);
    return 1;
}

int is_suicide(struct Board* board, struct Move move) {
    if (board->grid[move.pos.x][move.pos.y] != EMPTY) {
        return 0;
    }
    struct Board* board_copy = malloc(sizeof(struct Board));
    memcpy(board_copy, board, sizeof(struct Board));
    enum Result result = play_move(board_copy, move);
    if (result == BLACK_WINS || result == WHITE_WINS) {
        free(board_copy);
        return 1;
    }
    free(board_copy);
    return 0;
}

int is_legal(struct Board* board, struct Move move) {
    if (is_ko(board, move)) {
        return 0;
    }
    if (is_suicide(board, move)) {
        return 0;
    }
    return 1;
}

int main() {
    struct Board* board = init_board();
    while (1) {
        print_board(board);
        printf("%c to move: ", board->next_player == BLACK ? 'B' : 'W');
        char input[4];
        fgets(input, 4, stdin);
        struct Move move;
        if (!parse_move(input, &move)) {
            printf("Invalid input\n");
            continue;
        }
        if (!is_legal(board, move)) {
            printf("Illegal move\n");
            continue;
        }
        enum Result result = play_move(board, move);
        if (result != CONTINUE) {
            print_board(board);
            switch (result) {
                case BLACK_WINS:
                    printf("Black wins!\n");
                    break;
                case WHITE_WINS:
                    printf("White wins!\n");
                    break;
                case DRAW:
                    printf("Draw!\n");
                    break;
            }
            break;
        }
    }
    free(board);
    return 0;
}

该程序实现了围棋的基本规则，包括吃子、计算外气和禁手规则。在每次玩家输入一个落子时，程序会检查该落子是否合法，如果不合法则提示玩家重新输入。当一方胜利或游戏结束时，程序会输出胜利方并结束游戏。

### 回答2：
Codeblocks是一个开发环境，可以用来编写、调试和运行各种编程语言的程序。对于围棋双人对战程序，可以使用C语言来实现。

首先，我们需要定义一个二维数组来表示棋盘。可以使用int类型的数组来表示，0表示空位，1表示黑子，2表示白子。例如，定义一个15x15的棋盘可以使用以下代码：

int board[15][15];

接下来，我们需要实现落子和吃子的功能。当玩家选择在一个空位落子时，我们可以将该位置的值设置为1（黑子）或2（白子）。当玩家选择某个位置时，我们需要检查该位置周围的相邻位置是否有对方的子，如果有，则需要判断该位置的子是否可以吃掉对方的子。如果可以吃掉对方的子，我们需要将对方的子从棋盘上清除。

然后，我们还需要实现计算每个棋子的外气的功能。外气是指一个棋子周围空位的数量。我们可以定义一个函数来计算某个棋子的外气数量。函数会遍历该棋子周围的位置，统计空位的数量并返回。

最后，我们还需要实现禁手规则的功能。禁手规则是为了保证游戏的公平性和平衡性。在围棋中，有些形势下是不允许下子的，既不允许黑方也不允许白方在该位置落子。我们可以定义一个禁手检测函数，当玩家选择落子时，会判断该位置是否违反禁手规则。如果违反禁手规则，我们需要提示玩家选择其他位置。

综上所述，我们可以使用C语言来实现codeblocks的围棋双人对战程序，并包含吃子、计算外气和禁手规则的代码。这个程序可以通过给定的棋盘和玩家选择来实现落子、吃子、计算外气和检测禁手等功能。

### 回答3：
Codeblocks是一款流行的集成开发环境，适用于C语言编程。在C语言中，实现围棋双人对战程序涉及到吃子、计算外气和禁手规则等功能。以下是一个大致的代码示例：

#include <stdio.h>
#include <stdlib.h>

// 定义棋盘大小
#define SIZE 19

// 定义棋盘数组
int board[SIZE][SIZE];

// 定义黑白棋子的常数
#define BLACK 1
#define WHITE -1

// 检查某一位置是否合法
int is_valid(int x, int y) {
return x >= 0 && x < SIZE && y >= 0 && y < SIZE && board[x][y] == 0;
}

// 检查某一位置是否有气
int has_liberty(int x, int y) {
return (is_valid(x-1, y) && board[x-1][y] == 0) ||
(is_valid(x+1, y) && board[x+1][y] == 0) ||
(is_valid(x, y-1) && board[x][y-1] == 0) ||
(is_valid(x, y+1) && board[x][y+1] == 0);
}

// 检查某一位置是否被围住
int is_captured(int x, int y) {
return !has_liberty(x, y);
}

// 在某一位置放置棋子
void place_stone(int x, int y, int color) {
board[x][y] = color;
}

// 尝试吃掉某一位置的棋子及其相邻的被围住的棋子
void try_capture(int x, int y, int color) {
if (!is_valid(x, y) || board[x][y] == color)
return;
if (is_captured(x, y)) {
board[x][y] = 0;
try_capture(x-1, y, color);
try_capture(x+1, y, color);
try_capture(x, y-1, color);
try_capture(x, y+1, color);
}
}

// 检查某一位置是否符合禁手规则
int is_ko_rule(int x, int y, int color) {
int temp_board[SIZE][SIZE];
for (int i = 0; i < SIZE; i++) {
for (int j = 0; j < SIZE; j++) {
temp_board[i][j] = board[i][j];
}
}
temp_board[x][y] = color;
// TODO: 对禁手规则进行判断
return 0;
}

int main() {
// 初始化棋盘
for (int i = 0; i < SIZE; i++) {
for (int j = 0; j < SIZE; j++) {
board[i][j] = 0;
}
}

// TODO: 实现游戏逻辑，包括交替落子、判断吃子等功能

return 0;
}

这段代码实现了一个简化版的围棋双人对战程序，包含了吃子、计算外气和禁手规则的功能。具体的游戏逻辑需要进一步完善，例如交替落子、判断吃子等功能。希望能对你有所帮助。