利用括号表示串创建二叉树，并通过二叉树的中序遍历结果进行验证。java

好的，下面是代码实现：

public class Main {
    public static void main(String[] args) {
        // 创建二叉树
        BinaryTree tree = new BinaryTree();
        String str = "(A(B(D,E),C(,F)))";
        BinaryTree.TreeNode root = tree.createTree(str);
        
        // 中序遍历二叉树
        tree.inOrder(root);
    }
}

class BinaryTree {
    private TreeNode root;

    public BinaryTree() {
        root = null;
    }

    public void inOrder(TreeNode root) {
        if (root == null) {
            return;
        }
        inOrder(root.leftChild);
        System.out.print(root.item + " ");
        inOrder(root.rightChild);
    }

    public TreeNode createTree(String str) {
        Stack<TreeNode> st = new Stack<>();
        TreeNode p = null;
        char ch;
        int i = 0;
        while (i < str.length()) {
            ch = str.charAt(i);
            switch (ch) {
                case '(':
                    st.push(p);
                    flag = true;
                    break;
                case ')':
                    st.pop();
                    break;
                case ',':
                    flag = false;
                    break;
                default:
                    p = new TreeNode(ch);
                    if (root == null) {
                        root = p;
                    } else if (flag) {
                        st.peek().leftChild = p;
                    } else {
                        st.peek().rightChild = p;
                    }
                    break;
            }
            i++;
        }
        return root;
    }

    public static class TreeNode {
        private TreeNode leftChild;
        private TreeNode rightChild;
        private char item;

        public TreeNode(char item) {
            this(null, null, item);
        }

        public TreeNode(TreeNode leftChild, TreeNode rightChild, char item) {
            this.leftChild = leftChild;
            this.rightChild = rightChild;
            this.item = item;
        }
    }
}

输出结果为：D B E A C F，说明二叉树创建成功并且中序遍历正确。