C#代码实现求两条线段的交点

可以使用以下的C#代码来求解两条线段的交点：

using System;

class Program
{
    static void Main(string[] args)
    {
        // 定义线段的起点和终点坐标
        double x1 = 1, y1 = 1;
        double x2 = 4, y2 = 5;
        double x3 = 2, y3 = 3;
        double x4 = 5, y4 = 7;

        // 计算线段的交点
        double[] intersectionPoint = GetIntersectionPoint(x1, y1, x2, y2, x3, y3, x4, y4);

        // 输出交点坐标
        Console.WriteLine("Intersection Point: ({0}, {1})", intersectionPoint[0], intersectionPoint[1]);

        Console.ReadLine();
    }

    static double[] GetIntersectionPoint(double x1, double y1, double x2, double y2, double x3, double y3, double x4, double y4)
    {
        double[] intersectionPoint = new double[2];

        // 计算线段的参数
        double dx1 = x2 - x1;
        double dy1 = y2 - y1;
        double dx2 = x4 - x3;
        double dy2 = y4 - y3;

        // 计算两条线段的斜率
        double slope1 = dy1 / dx1;
        double slope2 = dy2 / dx2;

        // 计算两条线段的截距
        double intercept1 = y1 - slope1 * x1;
        double intercept2 = y3 - slope2 * x3;

        // 若两条线段平行，则没有交点
        if (slope1 == slope2)
        {
            Console.WriteLine("No intersection point");
            return intersectionPoint;
        }

        // 计算交点的x坐标
        double intersectionX = (intercept2 - intercept1) / (slope1 - slope2);

        // 计算交点的y坐标
        double intersectionY = slope1 * intersectionX + intercept1;

        // 将交点坐标存储到数组中
        intersectionPoint[0] = intersectionX;
        intersectionPoint[1] = intersectionY;

        return intersectionPoint;
    }
}

这段代码通过求解两条线段的斜率和截距，然后利用斜截式方程计算交点的坐标。如果两条线段平行，则没有交点。运行以上代码将输出交点的坐标。请根据实际情况修改线段的起点和终点坐标。