python小游戏编程代码

Python是一种非常适合初学者的小游戏编程语言，它拥有简洁的语法和丰富的库，如Pygame，可以帮助你快速上手。以下是一个简单的使用Pygame库创建的井字棋（Tic Tac Toe）游戏代码示例：

import pygame
import sys

# 初始化pygame
pygame.init()

# 设置窗口大小
window_size = (400, 400)
screen = pygame.display.set_mode(window_size)

# 定义颜色
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)

# 字符
X = 'X'
O = 'O'
BLANK = '_'

# 游戏矩阵
board = [['_' for _ in range(3)] for _ in range(3)]

# 更新游戏状态的函数
def update_board(position, player):
    board[position][position] = player

# 判断是否胜利
def check_win(board):
    # ... (这里省略详细判断逻辑，你可以根据九宫格遍历和比较)

# 游戏主循环
running = True
while running:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            pos = pygame.mouse.get_pos()
            row, col = pos // 100, pos // 100
            if board[row][col] == BLANK:
                update_board((row, col), X if turn == 'X' else O)
                turn = 'O' if turn == 'X' else 'X'

    # 绘制
    screen.fill(BLACK)
    for i in range(3):
        for j in range(3):
            pygame.draw.rect(screen, WHITE, (100 * j, 100 * i, 100, 100))
            text = board[i][j]
            font = pygame.font.SysFont(None, 50)
            text_surface = font.render(text, True, WHITE)
            screen.blit(text_surface, (100 * j + 50, 100 * i + 50))

    # 检查并显示结果
    winner = check_win(board)
    if winner:
        screen.fill(BLACK)
        font = pygame.font.SysFont(None, 70)
        text = 'Player ' + winner + ' wins!'
        text_surface = font.render(text, True, WHITE)
        screen.blit(text_surface, (window_size // 2 - text_surface.get_width() // 2, window_size // 2 - text_surface.get_height() // 2))
    
    # 更新屏幕
    pygame.display.flip()

# 关闭窗口
pygame.quit()
sys.exit()