kn(indices,n)=z(n+k_range).*conj(z(n-k_range));

import pandas as pd import numpy as np from keras.models import load_model # 加载已经训练好的kerasBP模型 model = load_model('D://model.h5') # 读取Excel文件中的数据 data = pd.read_excel('D://数据1.xlsx', sheet_name='4') # 对数据进行预处理，使其符合模型的输入要求# 假设模型的输入是一个包含4个特征的向量# 需要将Excel中的数据转换成一个(n, 4)的二维数组 X = data[['A', 'B', 'C', 'D']].values # 使用模型进行预测 y_pred = model.predict(X) # 对预测结果进行反归一化 y_pred_int = scaler_y.inverse_transform(y_pred).round().astype(int) # 构建带有概率的预测结果 y_pred_prob = pd.DataFrame(y_pred_int, columns=data.columns[:4]) mse = ((y_test - y_pred) 2).mean(axis=None) y_pred_prob['Probability'] = 1 / (1 + mse - ((y_pred_int - y_test) 2).mean(axis=None)) # 过滤掉和值超过6或小于6的预测值 y_pred_filtered = y_pred_prob[(y_pred_prob.iloc[:, :4].sum(axis=1) == 6)] # 去除重复的行 y_pred_filtered = y_pred_filtered.drop_duplicates() # 重新计算低于1.2的 Probability 值 low_prob_indices = y_pred_filtered[y_pred_filtered['Probability'] < 1.5].index for i in low_prob_indices: y_pred_int_i = y_pred_int[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_int_i) 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_int_i - y_test_i) 2).mean(axis=None)) y_pred_filtered.at[i, 'Probability'] = new_prob_i # 打印带有概率的预测结果 print('Predicted values with probabilities:') print(y_pred_filtered)

# 需要将Excel中的数据转换成一个(n, 4)的二维数组 X = data[['A', 'B', 'C', 'D']].values # 使用模型进行预测 y_pred = model.predict(X) # 对预测结果进行反归一化 y_pred_int = scaler_y.inverse_...

window_len = 64; % 窗口长度 N_guard = 16; % 保护间隔 N_train = 32; % 训练窗口长度 threshold = 3; % 判决门限 [range_indices, doppler_indices] = cfardetect(echo_mti, window_len, ... N_guard, N_train, threshold); range = range_indices * c / (2fs) lambda / 2; % 目标距离 doppler = (doppler_indices - n/2 - 1) * fs / n; % 目标多普勒频移中的cfardetect的代码是什么

function [range_indices, doppler_indices] = cfardetect(echo_mti, window_len, N_guard, N_train, threshold) [n, m] = size(echo_mti); RDM = zeros(n - N_guard - N_train + 1, m - window_len + 1); for i ...

import pandas as pd from keras.models import load_model from sklearn.preprocessing import MinMaxScaler # 加载已经训练好的kerasBP模型 model = load_model('D://model.h5') # 读取Excel文件中的数据 data = pd.read_excel('D://数据1.xlsx', sheet_name='4') # 对数据进行预处理，使其符合模型的输入要求 # 假设模型的输入是一个包含4个特征的向量 # 需要将Excel中的数据转换成一个(n, 4)的二维数组 X = data[['A', 'B', 'C', 'D']].values # 使用模型进行预测 y_pred = model.predict(X) scaler_y = MinMaxScaler(feature_range=(0, 4)) # 对预测结果进行反归一化 y_pred_int = scaler_y.inverse_transform(y_pred).round().astype(int) # 构建带有概率的预测结果 y_pred_prob = pd.DataFrame(y_pred_int, columns=data.columns[:4]) # 计算 mse y_test = data['y_true'].values mse = ((y_test - y_pred) 2).mean(axis=None) # 计算每个预测结果的概率并添加到 y_pred_prob 中 y_pred_prob['Probability'] = 1 / (1 + mse - ((y_pred_int - y_test) 2).mean(axis=None)) # 过滤掉和值超过6或小于6的预测值 y_pred_filtered = y_pred_prob[(y_pred_prob.iloc[:, :4].sum(axis=1) == 6)] # 去除重复的行 y_pred_filtered = y_pred_filtered.drop_duplicates() # 重新计算低于1.5的 Probability 值 low_prob_indices = y_pred_filtered[y_pred_filtered['Probability'] < 1.5].index for i in low_prob_indices: y_pred_int_i = y_pred_int[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_int_i) 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_int_i - y_test_i) 2).mean(axis=None)) y_pred_filtered.at[i, 'Probability'] = new_prob_i # 打印带有概率的预测结果 print('Predicted values with probabilities:') print(y_pred_filtered)这段程序中错误是由于使用了尚未拟合的MinMaxScaler实例导致的。在使用scikit-learn中的任何转换器之前，都需要先使用fit方法进行拟合，以便转换器可以学习数据的范围和分布。你需要在调用inverse_transform方法之前使用fit方法对MinMaxScaler进行拟合，代码怎么修改

# 需要将Excel中的数据转换成一个(n, 4)的二维数组 X = data[['A', 'B', 'C', 'D']].values # 使用模型进行预测 y_pred = model.predict(X) # 对预测结果进行反归一化 scaler_y = MinMaxScaler(feature_range=(0, ...

def forward(self, input_question, input_answer): question_embed = self.embedding(input_question) answer_embed = self.embedding(input_answer) _, question_hidden = self.encoder(question_embed) answer_outputs, _ = self.encoder(answer_embed, question_hidden) attention_weights = self.attention(answer_outputs).squeeze(dim=-1) attention_weights = torch.softmax(attention_weights, dim=1) context_vector = torch.bmm(attention_weights.unsqueeze(dim=1), answer_outputs).squeeze(dim=1) logits = self.decoder(context_vector) top_100_values, _ = torch.topk(logits, self.topk, dim=1) mask = torch.zeros_like(logits, requires_grad=True) # 设置 requires_grad=True weight = [] adds = [] for i in range(logits.size(0)): top_k_indices = torch.argsort(logits[i])[-self.topk:] mask_i = mask[i].clone() # 创建副本 mask_i[top_k_indices] = 1 - logits[i][top_k_indices] mask_1 = mask[i].clone() # 创建副本 mask_1[top_k_indices] = 1 weight.append(mask_1.clone()) # 创建副本并赋值回 mask adds.append(mask_i.clone()) # 创建副本并赋值回 mask score = (logits + torch.stack(adds)) * torch.stack(weight) return score

7. 对于每个样本，使用torch.topk函数选择得分最高的前k个值，并创建一个与logits相同形状的零张量作为mask。 8. 对于每个样本，根据得分最高的前k个值所在的索引，将mask中对应位置的值设置为1-logits中对应位置...

def forward(self, input_question, input_answer): question_embed = self.embedding(input_question) answer_embed = self.embedding(input_answer) _, question_hidden = self.encoder(question_embed) answer_outputs, _ = self.encoder(answer_embed, question_hidden) attention_weights = self.attention(answer_outputs).squeeze(dim=-1) attention_weights = torch.softmax(attention_weights, dim=1) context_vector = torch.bmm(attention_weights.unsqueeze(dim=1), answer_outputs).squeeze(dim=1) logits = self.decoder(context_vector) top_values, top_indices = torch.topk(logits.view(-1, vocab_size), k=self.topk, dim=1) return top_indices

根据您提供的代码，您可能会遇到以下错误：RuntimeError: element 0 of tensors does not require grad and does not have a grad_fn。这个错误通常发生在您在梯度计算过程中使用了不可训练的张量。...

def forward(self, input_question, input_answer): question_embed = self.embedding(input_question) answer_embed = self.embedding(input_answer) _, question_hidden = self.encoder(question_embed) answer_outputs, _ = self.encoder(answer_embed, question_hidden) attention_weights = self.attention(answer_outputs).squeeze(dim=-1) attention_weights = torch.softmax(attention_weights, dim=1) context_vector = torch.bmm(attention_weights.unsqueeze(dim=1), answer_outputs).squeeze(dim=1) logits = self.decoder(context_vector) top_100_values, _ = torch.topk(logits, self.topk, dim=1) # 在第1个维度上获取前100名的值 mask = torch.zeros_like(logits) # 创建与 input_question 相同形状的全零张量 # 对于每一行，将前100名的值设为1 for i in range(logits.size(0)): top_100_indices = torch.argsort(logits[i])[-self.topk:] # 获取前100名的索引 mask[i, top_100_indices] = 1 return mask 无法求导

top_100_indices = torch.argsort(logits[i])[-self.topk:] mask[i, top_100_indices] = 1 return mask 在修改后的代码中，我在创建mask张量时设置了requires_grad=True，以使其成为可求导的张量。这样...

import pandas as pd import numpy as np from sklearn.preprocessing import MinMaxScaler from sklearn.model_selection import train_test_split from keras.models import Sequential from keras.layers import Dense # 读取Excel文件 data = pd.read_excel('D://数据3.xlsx', sheet_name='5') # 把数据分成输入和输出 X = data.iloc[:, 0:5].values y = data.iloc[:, 0:5].values # 对输入和输出数据进行归一化 scaler_X = MinMaxScaler(feature_range=(0, 5)) X = scaler_X.fit_transform(X) scaler_y = MinMaxScaler(feature_range=(0, 5)) y = scaler_y.fit_transform(y) # 将数据集分成训练集和测试集 X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=0) # 创建神经网络模型 model = Sequential() model.add(Dense(units=5, input_dim=5, activation='relu')) model.add(Dense(units=12, activation='relu')) model.add(Dense(units=5, activation='relu')) model.add(Dense(units=5, activation='linear')) # 编译模型 model.compile(loss='mean_squared_error', optimizer='sgd') # 训练模型 model.fit(X_train, y_train, epochs=300, batch_size=500) # 评估模型 score = model.evaluate(X_test, y_test, batch_size=1500) # 使用训练好的模型进行预测 X_test_scaled = scaler_X.transform(X_test) y_pred = model.predict(X_test_scaled) # 对预测结果进行反归一化 y_pred_int = scaler_y.inverse_transform(y_pred).round().astype(int) # 构建带有概率的预测结果 y_pred_prob = pd.DataFrame(y_pred_int, columns=data.columns[:5]) mse = ((y_test - y_pred) 2).mean(axis=None) y_pred_prob['Probability'] = 1 / (1 + mse - ((y_pred_int - y_test) 2).mean(axis=None)) # 过滤掉和值超过5或小于5的预测值 row_sums = np.sum(y_pred, axis=1) y_pred_filtered = y_pred[(row_sums >= 5) & (row_sums <= 5), :] # 去除重复的行 y_pred_filtered = y_pred_filtered.drop_duplicates() # 重新计算低于1.2的 Probability 值 low_prob_indices = y_pred_filtered[y_pred_filtered['Probability'] < 1.5].index for i in low_prob_indices: y_pred_int_i = y_pred_int[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_int_i) 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_int_i - y_test_i) 2).mean(axis=None)) y_pred_filtered.at[i, 'Probability'] = new_prob_i # 打印带有概率的预测结果 print('Predicted values with probabilities:') print(y_pred_filtered) # 保存模型 model.save('D://大乐透5.h5')程序中显示Python 的错误提示，提示中提到了一个 'numpy.ndarray' 对象没有 'drop_duplicates' 属性。这可能是因为你将一个 numpy 数组传递给了 pandas 的 DataFrame.drop_duplicates() 方法，而这个方法只能用于 pandas 的 DataFrame 类型数据。你可以尝试将 numpy 数组转换为 pandas 的 DataFrame 对象，然后再进行去重操作这个怎么改

你需要将 y_pred_filtered 从 numpy 数组转换成 pandas 的 DataFrame 对象，然后再进行去重操作。可以使用 pd.DataFrame() 将 y_pred_filtered 转换成 DataFrame 对象，然后再使用 drop_duplicates() 方法...

User def init(self, primary_indices, secondary_indices, batch_size, secondary_batch_size): self.primary_indices = primary_indices self.secondary_indices = secondary_indices self.secondary_batch_size = secondary_batch_size self.primary_batch_size = batch_size - secondary_batch_size assert len(self.primary_indices) >= self.primary_batch_size > 0 assert len(self.secondary_indices) >= self.secondary_batch_size > 0代码解释

- primary_indices: 主要索引，是一个列表类型。 - secondary_indices: 次要索引，也是一个列表类型。 - batch_size: 批次大小，是一个整数类型。 - secondary_batch_size: 次要批次大小，也是一个整数类型。在...

def forward(self, input_question, input_answer): question_embed = self.embedding(input_question) answer_embed = self.embedding(input_answer) _, question_hidden = self.encoder(question_embed) answer_outputs, _ = self.encoder(answer_embed, question_hidden) attention_weights = self.attention(answer_outputs).squeeze(dim=-1) attention_weights = torch.softmax(attention_weights, dim=1) context_vector = torch.bmm(attention_weights.unsqueeze(dim=1), answer_outputs).squeeze(dim=1) logits = self.decoder(context_vector) top_100_values, _ = torch.topk(logits, self.topk, dim=1) mask = torch.zeros_like(logits, requires_grad=True) # 设置 requires_grad=True score = [] for i in range(logits.size(0)): top_100_indices = torch.argsort(logits[i])[-self.topk:] mask_i = mask[i].clone() # 创建副本 mask_i[top_100_indices] = 1.0 score.append(mask_i.clone()) # 创建副本并赋值回 mask score = torch.stack(score) return score 损失没有任何改变

score = [torch.where(torch.argsort(logits[i])[-self.topk:] == j, torch.tensor(1.0), mask[i, j]).clone() for i in range(logits.size(0)) for j in range(logits.size(1))] score = torch.stack(score) ...

import pandas as pd import numpy as np from sklearn.model_selection import train_test_split pd.set_option('display.max_columns', None) # 所有列 pd.set_option('display.max_rows', None) # 所有行 data = pd.read_excel('半监督数据.xlsx') X = data.drop(columns=['label']) # 特征矩阵 y = data['label'] # 标签列 # 划分数据集 X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.1, stratify=None, shuffle=True, random_state=0) # 划分带标签数据集 labeled_size = 0.3 n_labeled = int(labeled_size * len(X_train)) indices = np.arange(len(X_train)) unlabeled_indices = np.delete(indices, y_train.index[:n_labeled]) X_unlabeled = X_train.iloc[unlabeled_indices] y_unlabeled = y_train.iloc[unlabeled_indices] X_labeled = X_train.iloc[y_train.index[:n_labeled]] y_labeled = y_train.iloc[y_train.index[:n_labeled]] from sklearn import preprocessing pre_transform=preprocessing.StandardScaler() pre_transform.fit(np.vstack([train_datas, test_datas])) train_datas=pre_transform.transform(train_datas) test_datas=pre_transform.transform(train_datas) from LAMDA_SSL.Algorithm.Regression.CoReg import CoReg model=CoReg() model.fit(X=train_datas,y=labeled_y,test_datas=unlabeled_X) pred_y=model.predict(X=test_X) from LAMDA_SSL.Evaluation.Regressor.Mean_Squared_Error import Mean_Squared_Error performance = Mean_Squared_Error().scoring(test_y, pred_y)帮我看一下这段代码有什么问题？怎么修改？

indices = np.arange(len(X_train)) unlabeled_indices = np.delete(indices, y_train.index[:n_labeled]) X_unlabeled = X_train.iloc[unlabeled_indices] y_unlabeled = y_train.iloc[unlabeled_indices] X_...

PyOpenGL怎么绘制出特定曲面公式z=-0.000x^2+2.148xy-3.279y^2+0.262x-0.023*y+617.0的曲面

glVertex3f(X.flatten()[indices[i, 2]], Y.flatten()[indices[i, 2]], Z.flatten()[indices[i, 2]]) glEnd() glutSwapBuffers() glutInit() glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGBA | GLUT_DEPTH) ...

把这段代码里的location_embedding_dim去掉class my_GAT(torch.nn.Module): def init(self, in_channels, out_channels, n_heads, location_embedding_dim, filters_1, filters_2, dropout): super(my_GAT, self).init() self.in_channels = in_channels self.out_channels = out_channels self.n_heads = n_heads location_embedding_dim = 0 self.filters_1 = filters_1 self.filters_2 = filters_2 self.dropout = dropout self.location_embedding_dim = location_embedding_dim self.setup_layers() def setup_layers(self): self.GAT_1 = GATConv(in_channels=self.in_channels,out_channels=self.filters_1, heads=self.n_heads, dropout=0.1) self.GAT_2 = GATConv(in_channels=self.filters_1 * self.n_heads + self.location_embedding_dim, out_channels=self.out_channels, heads=self.n_heads, dropout=0.1, concat=False) def forward(self, edge_indices, features, location_embedding): features = torch.cat((features, location_embedding), dim=-1) features = self.GAT_1(features, edge_indices) features = torch.nn.functional.relu(features) features = torch.nn.functional.dropout(features, p=self.dropout, training=self.training) features = torch.cat((features, location_embedding), dim=-1) features = self.GAT_2(features, edge_indices) return features

self.GAT_2 = GATConv(in_channels=self.filters_1 * self.n_heads, out_channels=self.out_channels, heads=self.n_heads, dropout=0.1, concat=False) def forward(self, edge_indices, features, location_...

import pandas as pd import numpy as np from sklearn.model_selection import train_test_split from sklearn import preprocessing from LAMDA_SSL.Algorithm.Regression.CoReg import CoReg from LAMDA_SSL.Evaluation.Regressor.Mean_Squared_Error import Mean_Squared_Error pd.set_option('display.max_columns', None) # 所有列 pd.set_option('display.max_rows', None) # 所有行 data = pd.read_excel('半监督数据.xlsx') X = data.drop(columns=['label']) # 特征矩阵 y = data['label'] # 标签列 # 划分数据集 X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.1, stratify=None, shuffle=True, random_state=0) # 划分带标签数据集 labeled_size = 0.3 n_labeled = int(labeled_size * len(X_train)) indices = np.arange(len(X_train)) unlabeled_indices = np.delete(indices, y_train.index[:n_labeled]) X_unlabeled = X_train.iloc[unlabeled_indices] y_unlabeled = y_train.iloc[unlabeled_indices] X_labeled = X_train.iloc[y_train.index[:n_labeled]] y_labeled = y_train.iloc[y_train.index[:n_labeled]] # 数据预处理 pre_transform=preprocessing.StandardScaler() pre_transform.fit(np.vstack([X_train, X_test])) X_train = pre_transform.transform(X_train) X_test = pre_transform.transform(X_test) # 构建和训练模型 model = CoReg() model.fit(X=X_train, y=y_labeled, test_datas=X_unlabeled) pred_y = model.predict(X=X_test) # 计算性能指标 performance = Mean_Squared_Error().scoring(y_test, pred_y)代码运行不了，怎么修改？

indices = np.arange(len(X_train)) unlabeled_indices = np.delete(indices, y_train.index[:n_labeled]) X_unlabeled = X_train.iloc[unlabeled_indices] y_unlabeled = y_train.iloc[unlabeled_indices] X_...

indices = np.random.choice(range(iris_X.size),120,replace=False) iris_X.flat[indices] = 0

其中，np.random.choice(range(iris_X.size), 120, replace=False) 用于生成一个包含 120 个不重复随机索引的一维数组，iris_X.flat[indices] 用于获取这些随机索引对应的元素，并将它们的值设为 0。需要注意的...

kn(indices,n)=z(n+k_range).*conj(z(n-k_range));

y_pred_i = y_pred[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_i) 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_i - y_test_i) 2).mean(axis=None))重复的代码段(5 行长)怎么改

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kn(indices,n)=z(n+k_range).*conj(z(n-k_range));

y_pred_i = y_pred[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_i) ** 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_i - y_test_i) ** 2).mean(axis=None))重复的代码段(5 行长)怎么改

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y_pred_i = y_pred[i] y_test_i = y_test[i] mse_i = ((y_test_i - y_pred_i) 2).mean(axis=None) new_prob_i = 1 / (1 + mse_i - ((y_pred_i - y_test_i) 2).mean(axis=None))重复的代码段(5 行长)怎么改

PyOpenGL怎么绘制出特定曲面公式z=-0.000x^2+2.148xy-3.279y^2+0.262x-0.023*y+617.0的曲面