1、设计一个复数Complex 类，用友元函数重载乘法运算符(*)，用成员函数重载除法运算符(/)，完成两个复数对象的乘除法。 加法:(a+bi)+(c+di)=(a+c)+(b+d)i; 减法:(a+bi)-(c+di)=(a-c)+(b-d)i; 乘法:( (a+bi)∗(c+di)=(ac−bd)+(ad+bc)i; 除法:( (a+bi)/(c+di)=((a+bi)∗(c−di))/(c∗c+d∗d);要求一个完整的代码

好的，这是一个完整的代码实现，包括了复数类的定义和各种运算符的重载：

#include <iostream>

class Complex {
public:
    Complex(double r = 0, double i = 0);
    Complex operator+(const Complex& b) const;
    Complex operator-(const Complex& b) const;
    friend Complex operator*(const Complex& a, const Complex& b);
    Complex operator/(const Complex& b) const;
    friend std::ostream& operator<<(std::ostream& os, const Complex& c);
private:
    double real;
    double imag;
};

Complex::Complex(double r, double i) : real(r), imag(i) {}

Complex Complex::operator+(const Complex& b) const {
    return Complex(real + b.real, imag + b.imag);
}

Complex Complex::operator-(const Complex& b) const {
    return Complex(real - b.real, imag - b.imag);
}

Complex operator*(const Complex& a, const Complex& b) {
    double r = a.real * b.real - a.imag * b.imag;
    double i = a.real * b.imag + a.imag * b.real;
    return Complex(r, i);
}

Complex Complex::operator/(const Complex& b) const {
    double denominator = b.real * b.real + b.imag * b.imag;
    double r = (real * b.real + imag * b.imag) / denominator;
    double i = (imag * b.real - real * b.imag) / denominator;
    return Complex(r, i);
}

std::ostream& operator<<(std::ostream& os, const Complex& c) {
    os << c.real << " + " << c.imag << "i";
    return os;
}

int main() {
    Complex a(1, 2);
    Complex b(3, 4);
    Complex c = a * b;
    Complex d = a / b;
    Complex e = a + b;
    Complex f = a - b;
    std::cout << "a * b = " << c << std::endl;
    std::cout << "a / b = " << d << std::endl;
    std::cout << "a + b = " << e << std::endl;
    std::cout << "a - b = " << f << std::endl;
    return 0;
}

在这个代码中，我们定义了一个复数类 Complex，包含实部和虚部两个成员变量，以及构造函数和重载加法运算符(+)、减法运算符(-)、乘法运算符(*)、除法运算符(/)和输出流运算符(<<)的函数。在主函数中，我们创建了两个复数对象 a 和 b，对它们进行了四种运算，并输出结果。

希望这个完整的代码能够帮到你！