100个和尚吃了100个馒头,100和尚有大和尚和小和尚,一个大和尚能吃3馒头,三个小和尚吃1个馒头,问大和尚和小和尚有多少个?写出解决问题的java代码
时间: 2024-09-28 20:16:28 浏览: 96
这是一个经典的代数问题,可以通过设立方程组来求解。设大和尚有x个,小和尚有y个,则我们有以下两个等式:
1. x + y = 100 (总人数)
2. 3x + (1/3)y = 100 (总共吃的馒头数)
以下是对应的Java代码:
```java
import java.util.Scanner;
public class MonksAndBuns {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入和尚总数:");
int totalMonks = scanner.nextInt();
double totalBuns = totalMonks;
int bigMonksCount = 0;
while(totalBuns > 0 && bigMonksCount <= totalMonks){
double bunsForBigMonk = 3;
if(totalBuns >= bunsForBigMonk){
bigMonksCount++;
totalBuns -= bunsForBigMonk;
} else {
break;
}
}
int smallMonksCount = totalMonks - bigMonksCount;
System.out.printf("大和尚有 %d 个,小和尚有 %d 个。\n", bigMonksCount, smallMonksCount);
scanner.close();
}
}
```
当运行此程序并输入100时,它会给出大和尚和小和尚的具体数目。
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