有4个圆塔,圆心分别为(2,2)、(-2,2)、(-2,-2)、(2,一2),圆半径为 1,见图 4.17。这 4 个塔的高度为10m,塔以外无建筑物。今输人任一点的坐标,求该点的建筑高度(塔外的高度为零)。c语言

以下是C语言的代码实现，用于计算任意点的建筑高度：

#include <stdio.h>
#include <math.h>

#define TOWER_HEIGHT 10
#define TOWER_RADIUS 1

struct Point {
    double x;
    double y;
};

double distance(struct Point p1, struct Point p2) {
    return sqrt(pow(p1.x - p2.x, 2) + pow(p1.y - p2.y, 2));
}

double towerHeight(struct Point p) {
    struct Point towers[4] = {{2, 2}, {-2, 2}, {-2, -2}, {2, -2}};
    double max_height = 0;
    for (int i = 0; i < 4; i++) {
        double d = distance(p, towers[i]);
        if (d <= TOWER_RADIUS && TOWER_HEIGHT > max_height) {
            max_height = TOWER_HEIGHT;
        }
    }
    return max_height;
}

int main() {
    struct Point p = {1, 1};
    double height = towerHeight(p);
    printf("The height of the building at point (%.2f, %.2f) is %.2f meters.\n", p.x, p.y, height);
    return 0;
}