拔河游戏机verilog
时间: 2023-12-16 15:05:57 浏览: 75
以下是一个基于Verilog的拔河游戏机的实现,其中使用了FPGA芯片和VGA显示器。该游戏机可以支持两个玩家,每个玩家都有一个按钮,按下按钮可以向自己的一侧移动亮点。当亮点到达屏幕的一侧时,该玩家获胜。
```verilog
module Tug_of_War(
input clk, // 时钟信号
input rst, // 复位信号
input p1_btn, // 玩家1的按钮
input p2_btn, // 玩家2的按钮
output reg [6:0] led, // 7个发光二极管
output reg [9:0] vga_x, // VGA显示器的x坐标
output reg [9:0] vga_y // VGA显示器的y坐标
);
reg [1:0] state; // 状态机的状态
reg [1:0] winner; // 获胜者
reg [9:0] cnt; // 计数器
reg [9:0] p1_score; // 玩家1的得分
reg [9:0] p2_score; // 玩家2的得分
parameter IDLE = 2'b00; // 空闲状态
parameter PLAYING = 2'b01; // 游戏状态
parameter GAME_OVER = 2'b10; // 游戏结束状态
// 初始化
initial begin
state <= IDLE;
winner <= 2'b00;
cnt <= 10'd0;
p1_score <= 10'd0;
p2_score <= 10'd0;
end
// 状态机
always @(posedge clk) begin
if (rst) begin
state <= IDLE;
winner <= 2'b00;
cnt <= 10'd0;
p1_score <= 10'd0;
p2_score <= 10'd0;
end else begin
case (state)
IDLE: begin
led <= 7'b0100000; // 中间的发光二极管亮
vga_x <= 10'd0;
vga_y <= 10'd0;
if (p1_btn && !p2_btn) begin
state <= PLAYING;
winner <= 2'b01;
end else if (!p1_btn && p2_btn) begin
state <= PLAYING;
winner <= 2'b10;
end
end
PLAYING: begin
if (cnt == 10'd10) begin
cnt <= 10'd0;
if (winner == 2'b01) begin
p1_score <= p1_score + 10'd1;
vga_x <= p1_score;
vga_y <= 10'd0;
if (p1_score == 10'd511) begin
state <= GAME_OVER;
end else begin
winner <= 2'b10;
end
end else if (winner == 2'b10) begin
p2_score <= p2_score + 10'd1;
vga_x <= p2_score;
vga_y <= 10'd0;
if (p2_score == 10'd511) begin
state <= GAME_OVER;
end else begin
winner <= 2'b01;
end
end
end else begin
cnt <= cnt + 10'd1;
if (p1_btn && !p2_btn) begin
winner <= 2'b01;
end else if (!p1_btn && p2_btn) begin
winner <= 2'b10;
end
end
end
GAME_OVER: begin
led <= 7'b0000001; // 最左边的发光二极管亮
vga_x <= 10'd0;
vga_y <= 10'd0;
if (p1_btn && !p2_btn) begin
state <= IDLE;
end else if (!p1_btn && p2_btn) begin
state <= IDLE;
end
end
endcase
end
end
endmodule
```
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