一元多项式的求和(附加代码模式)
时间: 2024-04-14 10:19:44 浏览: 8
一元多项式的求和可以通过以下步骤完成:
1. 首先,创建两个一元多项式的指针,并使用函数CreatePolynomial()将多项式的系数和指数输入到计算机中。
2. 接下来,使用函数PrintPolynomial()将这两个一元多项式输出。
3. 然后,调用函数CombinePolynomial()将两个一元多项式相加,并将结果输出。
4. 最后,将计算结果返回给主函数main完成整个求和过程。
以下是一个C语言的示例代码,可以帮助你理解和实现一元多项式的求和:
```c
// 头文件 Poly.h
typedef struct {
float coef; // 系数
int expon; // 指数
} Polynomial;
Polynomial* CreatePolynomial(int termCount);
void PrintPolynomial(Polynomial* poly, int termCount);
void CombinePolynomial(Polynomial* poly1, int termCount1, Polynomial* poly2, int termCount2);
// 源文件 Poly.c
#include <stdio.h>
#include <stdlib.h>
#include "Poly.h"
Polynomial* CreatePolynomial(int termCount) {
Polynomial* poly = (Polynomial*)malloc(termCount * sizeof(Polynomial));
for (int i = 0; i < termCount; i++) {
printf("请输入第%d项的系数和指数:", i + 1);
scanf("%f%d", &(poly[i].coef), &(poly[i].expon));
}
return poly;
}
void PrintPolynomial(Polynomial* poly, int termCount) {
for (int i = 0; i < termCount; i++) {
printf("%.2fx^%d ", poly[i].coef, poly[i].expon);
if (i < termCount - 1) {
printf("+ ");
}
}
printf("\n");
}
void CombinePolynomial(Polynomial* poly1, int termCount1, Polynomial* poly2, int termCount2) {
int i = 0, j = 0;
while (i < termCount1 && j < termCount2) {
if (poly1[i].expon > poly2[j].expon) {
printf("%.2fx^%d ", poly1[i].coef, poly1[i].expon);
i++;
} else if (poly1[i].expon < poly2[j].expon) {
printf("%.2fx^%d ", poly2[j].coef, poly2[j].expon);
j++;
} else {
float sum = poly1[i].coef + poly2[j].coef;
if (sum != 0) {
printf("%.2fx^%d ", sum, poly1[i].expon);
}
i++;
j++;
}
}
while (i < termCount1) {
printf("%.2fx^%d ", poly1[i].coef, poly1[i].expon);
i++;
}
while (j < termCount2) {
printf("%.2fx^%d ", poly2[j].coef, poly2[j].expon);
j++;
}
printf("\n");
}
int main() {
int termCount1, termCount2;
printf("请输入第一个一元多项式的项数:");
scanf("%d", &termCount1);
Polynomial* poly1 = CreatePolynomial(termCount1);
printf("第一个一元多项式为:");
PrintPolynomial(poly1, termCount1);
printf("请输入第二个一元多项式的项数:");
scanf("%d", &termCount2);
Polynomial* poly2 = CreatePolynomial(termCount2);
printf("第二个一元多项式为:");
PrintPolynomial(poly2, termCount2);
printf("两个一元多项式的求和结果为:");
CombinePolynomial(poly1, termCount1, poly2, termCount2);
free(poly1);
free(poly2);
return 0;
}
```