用c语言写一个五子棋小游戏

好的，以下是用C语言实现的五子棋小游戏代码。

#include <stdio.h>
#include <stdlib.h>

#define ROW 15
#define COL 15

char board[ROW][COL];
int player = 1;

void init_board() {
  int i, j;
  for (i = 0; i < ROW; i++) {
    for (j = 0; j < COL; j++) {
      board[i][j] = '+';
    }
  }
}

void print_board() {
  int i, j;
  printf(" ");
  for (i = 0; i < COL; i++) {
    printf(" %2d", i + 1);
  }
  printf("\n");
  for (i = 0; i < ROW; i++) {
    printf("%2d", i + 1);
    for (j = 0; j < COL; j++) {
      printf(" %2c", board[i][j]);
    }
    printf("\n");
  }
}

int check_win(int row, int col) {
  char c = player == 1 ? 'O' : 'X';
  int count = 0, i, j;

  // 横向检查
  for (i = col - 4; i <= col; i++) {
    if (i < 0 || i + 4 >= COL) {
      continue;
    }
    count = 0;
    for (j = i; j <= i + 4; j++) {
      if (board[row][j] == c) {
        count++;
      } else {
        break;
      }
    }
    if (count == 5) {
      return 1;
    }
  }

  // 纵向检查
  for (i = row - 4; i <= row; i++) {
    if (i < 0 || i + 4 >= ROW) {
      continue;
    }
    count = 0;
    for (j = i; j <= i + 4; j++) {
      if (board[j][col] == c) {
        count++;
      } else {
        break;
      }
    }
    if (count == 5) {
      return 1;
    }
  }

  // 左上到右下斜向检查
  for (i = row - 4, j = col - 4; i <= row && j <= col; i++, j++) {
    if (i < 0 || i + 4 >= ROW || j < 0 || j + 4 >= COL) {
      continue;
    }
    count = 0;
    int k;
    for (k = 0; k < 5; k++) {
      if (board[i + k][j + k] == c) {
        count++;
      } else {
        break;
      }
    }
    if (count == 5) {
      return 1;
    }
  }

  // 右上到左下斜向检查
  for (i = row - 4, j = col + 4; i <= row && j >= col; i++, j--) {
    if (i < 0 || i + 4 >= ROW || j < 0 || j - 4 >= COL) {
      continue;
    }
    count = 0;
    int k;
    for (k = 0; k < 5; k++) {
      if (board[i + k][j - k] == c) {
        count++;
      } else {
        break;
      }
    }
    if (count == 5) {
      return 1;
    }
  }

  return 0;
}

int main() {
  int row, col;
  init_board();
  print_board();
  while (1) {
    printf("Player %d's turn:\n", player);
    printf("Row: ");
    scanf("%d", &row);
    printf("Col: ");
    scanf("%d", &col);

    if (board[row - 1][col - 1] != '+') {
      printf("Invalid move, please try again.\n");
      continue;
    }

    board[row - 1][col - 1] = player == 1 ? 'O' : 'X';
    print_board();

    if (check_win(row - 1, col - 1)) {
      printf("Player %d wins!\n", player);
      break;
    }

    player = player == 1 ? 2 : 1;
  }

  return 0;
}

该代码实现了一个基本的五子棋小游戏，玩家可以在控制台输入行和列坐标下棋，并且可以检查胜利条件。该代码中使用了一个二维字符数组来表示棋盘，初始化时将所有元素设置为加号，表示棋盘为空。玩家下棋时，程序会检查该位置是否为空，如果不为空，则提示玩家重新输入。每次下棋后，程序会检查是否有一方获胜，如果有则结束游戏并宣布胜利者。