Input an integer n. Display the square of 1 to n Input: An integer Output: The squares of 1 to n separated by comma.
时间: 2024-05-11 12:17:33 浏览: 76
Sure, I can help you with that. Here's the code to display the squares of 1 to n, separated by a comma:
```
n = int(input("Enter a number: "))
squares = [str(i**2) for i in range(1, n+1)]
print(", ".join(squares))
```
Let me know if you have any other questions!
相关问题
What is the recursion for computing the sum of the squares of the first n natural numbers? Denote it by Q(n).
The recursion for computing the sum of the squares of the first n natural numbers is:
Q(n) = Q(n-1) + n^2
with initial condition Q(0) = 0.
In other words, to compute Q(n), we can first compute Q(n-1) and then add n^2 to it. This process continues until we reach the base case Q(0), which is defined to be 0.
Write a program: input wo integers, calculate the difference ofsquares..
Sure, here's a Python program that takes two integers as input from the user, and calculates the difference of their squares:
```python
x = int(input("Enter the first integer: "))
y = int(input("Enter the second integer: "))
diff_of_squares = x ** 2 - y ** 2
print("The difference of squares is:", diff_of_squares)
```
In this program, we first prompt the user to enter two integers, `x` and `y`. We then calculate the difference of their squares using the formula:
- Difference of squares = x^2 - y^2
Finally, we print out the result to the user.
Note that we use the `**` operator to calculate the square of each integer. This operator raises a number to a power, so `x ** 2` means `x` raised to the power of 2 (i.e., `x` squared).