gps坐标转大地直角坐标代码c++

以下是C++代码示例，可以将GPS坐标转换为大地直角坐标：

#include <iostream>
#include <cmath>

using namespace std;

const double pi = 3.14159265358979323846; // 圆周率

// WGS84椭球参数
const double a = 6378137.0; // 长半轴
const double f = 1 / 298.257223563; // 扁率

// 弧度转角度
double radToDeg(double rad) {
    return rad * 180 / pi;
}

// 角度转弧度
double degToRad(double deg) {
    return deg * pi / 180;
}

// 计算子午线弧长
double meridianLength(double B) {
    double e2 = 2 * f - f * f;
    double A = a * (1 - e2);
    double B0 = degToRad((int)(B / 1) * 1);
    double s = A * (1 - e2) / pow(1 - e2 * sin(B0) * sin(B0), 1.5);
    double t = tan(B0);
    double C = e2 * cos(B0) * cos(B0);
    double p = pow(cos(B0), 2);
    double N = a / sqrt(1 - e2 * sin(B0) * sin(B0));
    double M = a * (1 - e2) / pow(1 - e2 * sin(B0) * sin(B0), 1.5);
    double d = degToRad(B - (int)(B / 1) * 1);
    double L = A / N;
    double H = L * L / 2 * sin(B0) * cos(B0);
    double E = d * pow(L, 2) / 2 * pow(cos(B0), 2);
    double F = d * pow(L, 4) / 24 * pow(cos(B0), 4) * (5 - t * t + 9 * C + 4 * C * C);
    double G = d * pow(L, 6) / 720 * pow(cos(B0), 6) * (61 - 58 * t * t + pow(t, 4));
    double S = s * d + H * pow(d, 3) / 6 + E + F + G;
    return S;
}

// GPS坐标转大地直角坐标
void gpsToRectangular(double B, double L, double H, double &X, double &Y, double &Z) {
    double e2 = 2 * f - f * f;
    double N = a / sqrt(1 - e2 * sin(B) * sin(B));
    X = (N + H) * cos(B) * cos(L);
    Y = (N + H) * cos(B) * sin(L);
    Z = (N * (1 - e2) + H) * sin(B);
}

int main() {
    double B = degToRad(30.0); // 纬度
    double L = degToRad(120.0); // 经度
    double H = 0.0; // 高程
    double X, Y, Z;
    gpsToRectangular(B, L, H, X, Y, Z);
    cout << X << ", " << Y << ", " << Z << endl;
    return 0;
}

注：本代码仅供参考，实际使用时需要根据实际情况进行调整和验证。