求s=s1的值是=1+1/2+1/3+...1/n

求s=s1的值是=1+1/2+1/3+...1/n的方法有两种：
1. 使用for循环计算：

#include <stdio.h>

float fun(int n){
    int i;
    float s = 0.0;
    for(i = 1; i <= n; i++){
        s = s + 1.0 / i;
    }
    return s;
}

int main(){
    int n;
    float s;
    printf("Please enter N:");
    scanf("%d", &n);
    s = fun(n);
    printf("the result is: %f\n", s);
    return 0;
}

2. 使用while循环计算：

#include <stdio.h>

float fun(int n){
    int i = 1;
    float s = 0.0;
    while(i <= n){
        s = s + 1.0 / i;
        i++;
    }
    return s;
}

int main(){
    int n;
    float s;
    printf("Please enter N:");
    scanf("%d", &n);
    s = fun(n);
    printf("the result is: %f\n", s);
    return 0;
}