Failure to find com.winning.polaris.hmb:Polaris_hmb_parent:pom:${revision} in http://192.168.3.103:8081/nexus/content/repositories/public/ was cached in the local repository, resolution will not be reattempted until the update interval of snapshots has elapsed or updates are forced 这是什么问题

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Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'baseDataCfgEntry': Unsatisfied dependency expressed through field 'schemeConfigService'; nested exception is org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'schemeConfigServiceImpl': Unsatisfied dependency expressed through field 'dictUtil'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'dictUtil' defined in file [D:\Desktop\project\hou\group_insurance_claims\Polaris_hmb_comm\target\classes\com\winning\polaris\hmb\comm\util\DictUtil.class]: Initialization of bean failed; nested exception is com.alibaba.dubbo.rpc.RpcException: No provider available from registry 127.0.0.1:2181 for service com.winning.polaris.auth.api.service.BasicServiceSysService:1.0.0 on consumer 10.20.21.162 use dubbo version 2.0.1, please check status of providers(disabled, not registered or in blacklist).

这个异常是Spring容器在初始化bean时发生的错误，提示无法创建名为'baseDataCfgEntry'的bean，原因是该bean的依赖项'schemeConfigService'没有得到满足。进一步的错误信息显示，'schemeConfigService'依赖于'...

algorithmic trading: winning strategies and their rationale pdf

总而言之，《Algorithmic Trading: Winning Strategies and Their Rationale》这本书提供了关于算法交易的全面介绍，涵盖了各种策略、理论依据和实际应用。对于对算法交易感兴趣的人来说，这本书是一本必读的参考...

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total_stake = sum([node.stake_amount for node in self.nodes]) winning_num = random.uniform(0, total_stake) current_num = 0 for node in self.nodes: current_num += node.stake_amount if current_num...

http://search.ccgp.gov.cn/bxsearch，帮我用python在这个网址写一个爬虫程序，要求爬取2016年1月1日年至2023年7月12日的信息化项目招标中标数据，注意数据查询间隔时间不能超过365天，需要分段时间间隔查询。其中限定采购人为中央企业，其他企业搜索结果过滤掉。将所爬取的每一条数据存入excel表格，并注明每一条数据的招标公告网址url

winning_bidder = result.find('span', class_='vT-srch-result-list-bidUnit').get_text() # 获取采购人 buyer = result.find('span', class_='vT-srch-result-list-bidOrg').get_text() # 获取中标金额 ...

用到以下类实现The division of responsibility between the different classes is as follows. - Die: Responsible for handling randomly generated integer values between 1 and 6. - DiceCup: Handles five objects (dice) of class Die. Has the ability to bank and release dice individually. Can also roll dice that are not banked. - ShipOfFoolsGame: Responsible for the game logic and has the ability to play a round of the game resulting in a score. Also has a property that tells what accumulated score results in a winning state, for example 21. - Player: Responsible for the score of the individual player. Has the ability, given a game logic, play a round of a game. The gained score is accumulated in the attribute score. - PlayRoom: Responsible for handling a number of players and a game. Every round the room lets each player play, and afterwards check if any player has reached the winning score. 3. Implementation

"""Rolls the die and sets its value to a random integer between 1 and 6.""" self.value = random.randint(1, 6) class DiceCup: """Class representing a cup containing five dice.""" def __init__(self...

UPDATE tb_executive_company a INNER JOIN tb_winning_company b ON a.order_id = b.id and a.policy = 'BKP' and b.policy = 'KP' SET a.policy = b.policy

这是一个 MySQL 的 UPDATE 语句，它将 tb_executive_company 表中的 policy 字段值为 'BKP'，且 order_id 字段与 tb_winning_company 表中的 id 字段匹配的记录，将它们的 policy 字段值更新为 'KP'。也就是说，将 ...

http://search.ccgp.gov.cn/bxsearch?searchtype=1&page_index=1&bidSort=0&buyerName=&projectId=&pinMu=0&bidType=1&dbselect=bidx&kw=%E4%BF%A1%E6%81%AF%E5%8C%96&start_time=2016%3A01%3A11&end_time=2016%3A07%3A12&timeType=6&displayZone=&zoneId=&pppStatus=0&agentName=，按照这个url格式帮我用python在这个网址写一个爬虫程序，要求爬取2016年1月1日年至2023年7月12日的信息化项目招标中标数据，注意数据查询间隔时间不能超过365天，需要分段时间间隔查询。其中限定采购人为中央企业，其他企业搜索结果过滤掉。将所爬取的每一条数据存入excel表格，并注明每一条数据的招标公告网址url

winning_bidder = result.find('span', class_='vT-srch-result-list-bidUnit').get_text() # 获取采购人 buyer = result.find('span', class_='vT-srch-result-list-bidOrg').get_text() # 获取中标金额 ...

for (Winning winning : winnings) { // 若存在物流信息发货时间不能为空 if (winning.getPostTime() != null){ rightNow.setTime(winning.getPostTime()); //日期加1个月 rightNow.add(Calendar.MONTH,1); flg = rightNow.getTime().compareTo(new Date()); if (flg <= 0 ){ flag = true; } } if (!VtuzxUtil.isEmpty(winning.getOutState())){ // 自动收货 if(winning.getOutState().equals(String.valueOf(PrizeOutStateEnum.Sent_ENUM.value())) && flag){ // 修改发放状态为已收货 winningDao.updOutStateById(String.valueOf(winning.getId()),PrizeOutStateEnum.Receive_Goods.value()); winning.setOutState(PrizeOutStateEnum.Receive_Goods.value()); flag = false; } } dataList.add( new VtuzxMap("prizeName",winning.getPrizeName()) .append("receiptNo",winning.getReceiptNo()) .append("companyName",winning.getCompanyName()) .append("department",winning.getDepartment()) .append("prizeNum",winning.getPrizeNum()) .append("outStore",winning.getOutStore()) .append("giveOut",winning.getGiveOut()) .append("userName",winning.getUserName()) .append("activityName",winning.getActivityName()) .append("outState",winning.getOutState()) .append("mobile",winning.getMobile()) .append("activityId",winning.getAwardActivityId()) .append("prizeType",winning.getPrizeType()) .append("clearingState",winning.getClearingState()) .append("postCompany",winning.getPostCompany()) .append("storeName", winning.getStoreName()) .append("postNo",winning.getPostNo()) .append("postName",winning.getPostName()) .append("contactMobile",winning.getContactMobile()) .append("province",winning.getProvince()) .append("city",winning.getCity()) .append("area",winning.getArea()) .append("createdAt",VtuzxUtil.formatYmdHmsF(winning.getCreatedAt())) .append("addressDetail",winning.getAddressDetail()) ); }使用stream优化

.filter(winning -> winning.getPostTime() != null) .map(winning -> { Calendar rightNow = Calendar.getInstance(); rightNow.setTime(winning.getPostTime()); rightNow.add(Calendar.MONTH, 1); boolean ...

def check_winner(move_sequence): winning_positions = [[0, 1, 2], [3, 4, 5], [6, 7, 8], [0, 3, 6], [1, 4, 7], [2, 5, 8], [0, 4, 8], [2, 4, 6]] player_moves = [[], []] for i, move in enumerate(move_sequence): player_moves[i % 2].append(int(move)) for positions in winning_positions: if all(pos in player_moves[0] for pos in positions): return "xiaoming wins." if all(pos in player_moves[1] for pos in positions): return "xiaohei wins." if len(move_sequence) == 9: return "drew." return "游戏进行中。" move_sequence = input() result = check_winner(move_sequence) print(result)

你提供的代码几乎与我之前给出的代码相同，只是在判断胜利的部分做了一些修改。这段代码会根据输入的数字判断小明和小黑谁赢了，或者是否平局。你可以输入一串数字来测试这个程序，例如输入 123456789，程序将...

根据以下要求编写一个python程序1. Description Ship of Fools is a simple classic dice game. It is played with five standard 6-faced dice by two or more players. - The goal of the game is to gather a 6, a 5 and a 4 (ship, captain and crew) in the mentioned order. - The sum of the two remaining dice (cargo) is preferred as high as possible. The player with the highest cargo score wins the round. Example: - In the first round turn, if a player rolls 6 4 3 3 1 (note we five dice at the beginning), the player can bank the 6 (ship), but the rest needs to be re-rolled since there is no 5. - In the second round turn, if the player rolls 6 5 4 4 (four dice, since the 6 from last turn is banked), the player can bank the 5 (captain) and the 4 (crew). The player has three choices for the remaining 6 and 4. The player can bank both and score 10 points, or re-roll one or two of the dice and hope for a higher score. - In the second round turn, if the player instead rolled 4 4 3 1, all dice needs to be re-rolled since there is no 5.程序需要包含一下几个类.The division of responsibility between the different classes is as follows. - Die: Responsible for handling randomly generated integer values between 1 and 6. - DiceCup: Handles five objects (dice) of class Die. Has the ability to bank and release dice individually. Can also roll dice that are not banked. - ShipOfFoolsGame: Responsible for the game logic and has the ability to play a round of the game resulting in a score. Also has a property that tells what accumulated score results in a winning state, for example 21. - Player: Responsible for the score of the individual player. Has the ability, given a game logic, play a round of a game. The gained score is accumulated in the attribute score. - PlayRoom: Responsible for handling a number of players and a game. Every round the room lets each player play, and afterwards check if any player has reached the winning score.

self.dice = [Die() for i in range(5)] self.banked = [False for i in range(5)] def roll(self): for i in range(5): if not self.banked[i]: self.dice[i].roll() def bank(self, index): self....

For this task you are required to write a class to represent a Dice. Your class should contain all features and functionality of a Die. Once you have your Dice class written you are going to write a very simple game. The game is one where each player has their own n sided Dice, and they win the game by being the first to reach a cumulative score after rolling their Dice. Your game should allow Dice the same n-sided dice for each player. The game should allow the number of players and the winning score to be decided by the user. It should print out the winning player the score they achieved and how many rolls it took them to achieve their score

To create a simple game using this class, we can do the following: python num_players = int(input("Enter the number of players: ")) num_sides = int(input("Enter the number of sides on the dice: ")...

You are given two positive integers, a and b (a<b ). For some positive integer n , two players will play a game starting with a pile of n stones. They take turns removing exactly a or exactly b stones from the pile. The player who is unable to make a move loses. Find a positive integer n such that the second player to move in this game has a winning strategy. This means that no matter what moves the first player makes, the second player can carefully choose their moves (possibly depending on the first player's moves) to ensure they win. 请帮我编写一个C++代码，并用中文解释

好的！下面是用C++编写的代码，并附有中文解释： cpp #include int main() { int t; std::cin >> t; // 输入测试用例的数量 ... // 选择一个 n，使得在游戏开始时，第二个玩家有必胜策略 ...这段代码首先读取测试...

针对第一个关卡，实现深度优先搜索 controllers.DepthFirst.java: 在游戏一开始就使用深度优先搜索找到成功的路径通关，记录下路径，并在之后每一步按照路径执行动作。注意在搜索时避免回路，可使用StateObservation类的equalPosition方法判断状态是否相等。由于搜索到通关路径所需时间较长，通过CompetitionParameters.ACTION_TIME来设置足够的时间来允许完成搜索。

// Found the winning state, record the path path.add(currentState); break; } if (!visited.contains(currentState)) { visited.add(currentState); path.add(currentState); for (Types.ACTIONS ...

Determine whether Player 1 has a winning strategy in the following finite Boolean games, where in both cases \mathrm{\Gamma}_1≔x1,x3 and Γ2≔x2,x4. \psi≔x1∧x3→¬x2∧¬x1→x1∧¬x2→x3∨x4 \psi≔x1∨¬x2∧x2∨x3∧¬x3∨¬x4∧¬x1∨¬x2∨x3∨x4

For the first game, we can construct the following truth table: x1 | x3 | x2 | x4 | Player 1 ---|----|----|----|---------- ... Therefore, Player 1 does not have a winning strategy in this game.

ERROR com.winning.polaris.container.jetty.server.JettyServer - moduleId:Polaris_hmb_mobile_web For input string: ""

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Determine whether Player 1 has a winning strategy in the following finite Boolean games, where in both cases \mathrm{\Gamma}_1≔x1,x3 and Γ2≔x2,x4. \psi≔x1∧x3→¬x2∧¬x1→x1∧¬x2→x3∨x4 \psi≔x1∨¬x2∧x2∨x3∧¬x3∨¬x4∧¬x1∨¬x2∨x3∨x4

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