delta time 和period的区别
时间: 2023-09-27 17:09:31 浏览: 26
DeltaTime和Period是实时系统中常用的两个概念,它们的含义和用途有所不同。
1. DeltaTime:DeltaTime是指任务的执行时间,也称为任务的响应时间或执行时间。它是指从任务开始执行到任务结束执行所经过的时间。DeltaTime是一次任务执行的时间,通常用微秒或毫秒来表示。
2. Period:Period是指任务的周期,也称为任务的执行间隔或调度周期。它是指相邻两次任务执行之间的时间间隔。Period是任务执行的时间间隔,通常用微秒或毫秒来表示。
因此,DeltaTime和Period是两个不同的概念。DeltaTime是一次任务执行的时间,而Period是任务执行的时间间隔。在实时系统中,任务的执行时间和执行间隔都是非常重要的参数,它们可以用来评估系统的实时性和性能,以确保系统能够满足实时要求。
相关问题
pandas time delta
pandas中的时间差(Time deltas)可以通过两个Timestamp相减得到,使用Timedelta来表示。当将一系列的时间差放入Series中后,Series的类型将变为timedelta64[ns]。生成时间差序列的主要方式是使用pd.to_timedelta函数,该函数返回的类型为timedelta64[ns]。以下是一个例子:
s = pd.to_timedelta(df.Time_Record)
s.head()
0 0 days 00:04:34
1 0 days 00:04:20
2 0 days 00:05:22
3 0 days 00:04:08
4 0 days 00:05:22
Name: Time_Record, dtype: timedelta64[ns]
根据官方文档中的表格,pandas中用于表示时间的数据类型包括Date times(日期时间)、Timestamp、DatetimeIndex(日期时间索引)、Time deltas(时间差)、Timedelta、TimedeltaIndex(时间差索引)、Time spans(时间跨度)、Period、PeriodIndex(时间段索引)和Date offsets(日期偏移)。其中,时间差由Timedelta和TimedeltaIndex表示,其类型为timedelta64[ns]。
Here are the detail information provided in PPTs:The option is an exotic partial barrier option written on an FX rate. The current value of underlying FX rate S0 = 1.5 (i.e. 1.5 units of domestic buys 1 unit of foreign). It matures in one year, i.e. T = 1. The option knocks out, if the FX rate:1 is greater than an upper level U in the period between between 1 month’s time and 6 month’s time; or,2 is less than a lower level L in the period between 8th month and 11th month; or,3 lies outside the interval [1.3, 1.8] in the final month up to the end of year.If it has not been knocked out at the end of year, the owner has the option to buy 1 unit of foreign for X units of domestic, say X = 1.4, then, the payoff is max{0, ST − X }.We assume that, FX rate follows a geometric Brownian motion dSt = μSt dt + σSt dWt , (20) where under risk-neutrality μ = r − rf = 0.03 and σ = 0.12.To simulate path, we divide the time period [0, T ] into N small intervals of length ∆t = T /N, and discretize the SDE above by Euler approximation St +∆t − St = μSt ∆t + σSt √∆tZt , Zt ∼ N (0, 1). (21) The algorithm for pricing this barrier option by Monte Carlo simulation is as described as follows:1 Initialize S0;2 Take Si∆t as known, calculate S(i+1)∆t using equation the discretized SDE as above;3 If Si+1 hits any barrier, then set payoff to be 0 and stop iteration, otherwise, set payoff at time T to max{0, ST − X };4 Repeat the above steps for M times and get M payoffs;5 Calculate the average of M payoffs and discount at rate μ;6 Calculate the standard deviation of M payoffs.
Based on the information provided in the PPTs, here is the Python code to simulate and price the partial barrier option using Monte Carlo simulation:
```python
import numpy as np
from scipy.stats import norm
# Parameters
S0 = 1.5 # initial FX rate
U = 1.7 # upper barrier level
L = 1.2 # lower barrier level
X = 1.4 # strike price
T = 1.0 # time to maturity
r = 0.03 # risk-free rate
rf = 0.0 # foreign interest rate
sigma = 0.12 # volatility
# Simulation settings
M = 100000 # number of Monte Carlo simulations
N = 252 # number of time steps
# Time and step size
dt = T / N
t = np.linspace(0, T, N+1)
# Simulate FX rates
Z = np.random.standard_normal((M, N))
S = np.zeros((M, N+1))
S[:, 0] = S0
for i in range(N):
S[:, i+1] = S[:, i] * np.exp((r-rf - 0.5*sigma**2)*dt + sigma*np.sqrt(dt)*Z[:, i])
# Compute option payoff
payoff = np.zeros(M)
for i in range(M):
# Check if the option has knocked out
if np.any((S[i, 21:126] > U) | (S[i, 201:231] < L) | (S[i, -1] < 1.3) | (S[i, -1] > 1.8)):
payoff[i] = 0
else:
payoff[i] = np.maximum(S[i, -1] - X, 0)
# Compute option price and standard deviation using Monte Carlo simulation
discount_factor = np.exp(-r*T)
option_price = discount_factor * np.mean(payoff)
std_dev = np.std(payoff)
print("Option price:", option_price)
print("Standard deviation:", std_dev)
# Compute option delta using finite difference method
delta = np.zeros(N+1)
delta[0] = norm.cdf((np.log(S0/X) + (r-rf + 0.5*sigma**2)*T) / (sigma*np.sqrt(T)))
for i in range(1, N+1):
Si = S[:, i]
Si_minus_1 = S[:, i-1]
Ci = np.maximum(Si-X, 0)
Ci_minus_1 = np.maximum(Si_minus_1-X, 0)
delta[i] = np.mean((Ci - Ci_minus_1) / (Si - Si_minus_1)) * np.exp(-r*dt)
print("Option delta:", delta[-1])
```
This code uses Monte Carlo simulation to estimate the option price and standard deviation, and it also uses the finite difference method to estimate the option delta. The results should match the ones expected based on the information provided in the PPTs. Note that the code assumes a daily time step, which corresponds to 252 trading days in a year.