python编写贪吃蛇程序

好的，我可以回答这个问题。以下是一个简单的 Python 贪吃蛇程序的代码：

import pygame
import random

# 初始化 Pygame
pygame.init()

# 定义颜色
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)

# 设置屏幕大小
SCREEN_WIDTH = 600
SCREEN_HEIGHT = 600
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))

# 设置游戏标题
pygame.display.set_caption("贪吃蛇")

# 定义蛇的初始位置和大小
snake_block_size = 10
snake_speed = 15
x1 = SCREEN_WIDTH / 2
y1 = SCREEN_HEIGHT / 2

# 定义蛇的移动方向
x1_change = 0
y1_change = 0

# 定义食物的位置
foodx = round(random.randrange(0, SCREEN_WIDTH - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, SCREEN_HEIGHT - snake_block_size) / 10.0) * 10.0

# 定义蛇的长度
snake_List = []
Length_of_snake = 1

# 定义字体
font_style = pygame.font.SysFont(None, 30)

# 定义得分函数
def Your_score(score):
    value = font_style.render("Your Score: " + str(score), True, WHITE)
    screen.blit(value, [0, 0])

# 定义蛇的绘制函数
def our_snake(snake_block_size, snake_List):
    for x in snake_List:
        pygame.draw.rect(screen, GREEN, [x[0], x[1], snake_block_size, snake_block_size])

# 开始游戏循环
game_over = False
while not game_over:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                x1_change = -snake_block_size
                y1_change = 0
            elif event.key == pygame.K_RIGHT:
                x1_change = snake_block_size
                y1_change = 0
            elif event.key == pygame.K_UP:
                y1_change = -snake_block_size
                x1_change = 0
            elif event.key == pygame.K_DOWN:
                y1_change = snake_block_size
                x1_change = 0

    # 判断蛇是否碰到边界
    if x1 >= SCREEN_WIDTH or x1 < 0 or y1 >= SCREEN_HEIGHT or y1 < 0:
        game_over = True

    # 移动蛇的位置
    x1 += x1_change
    y1 += y1_change

    # 绘制背景
    screen.fill(BLACK)

    # 绘制食物
    pygame.draw.rect(screen, BLUE, [foodx, foody, snake_block_size, snake_block_size])

    # 将蛇的位置添加到列表中
    snake_Head = []
    snake_Head.append(x1)
    snake_Head.append(y1)
    snake_List.append(snake_Head)

    # 判断蛇是否吃到了食物
    if x1 == foodx and y1 == foody:
        foodx = round(random.randrange(0, SCREEN_WIDTH - snake_block_size) / 10.0) * 10.0
        foody = round(random.randrange(0, SCREEN_HEIGHT - snake_block_size) / 10.0) * 10.0
        Length_of_snake += 1

    # 判断蛇是否碰到了自己
    if len(snake_List) > Length_of_snake:
        del snake_List[0]

    for x in snake_List[:-1]:
        if x == snake_Head:
            game_over = True

    # 绘制蛇
    our_snake(snake_block_size, snake_List)

    # 绘制得分
    Your_score(Length_of_snake - 1)

    # 更新屏幕
    pygame.display.update()

    # 控制蛇的速度
    clock = pygame.time.Clock()
    clock.tick(snake_speed)

# 退出 Pygame
pygame.quit()

希望能对你有所帮助！